基于SQL Server中的第一列在第二列上分组不同的值

Question

Please consider the below example :

id    name
1234   maria
1235   tamas
1236   helia
1234   maria
1235   jack
1235   david

What I want to do is to group the distinct value on the second column based on id :

id    name      id      name      id       name
1234  maria     1235    tamas     1236     helia
                1235    jack
                1235   david 

I am not sure, but I think I should use cursor on id and then select the second column by that id but I wasn't successful. Can somebody help me out in this?

Answer 1

Try this:

SELECT A.id, MAX(STUFF(B.name, 1, 1, '')) AS name 
FROM tableA A 
CROSS APPLY(SELECT ',' + A1.name FROM tableA A1 WHERE A.id = A1.id FOR XML PATH('')) AS B (name)
GROUP BY A.id

Answer 2

Distinct keyword should solve the purpose:

declare @test table ( id int, name varchar(20))

insert into @test values 
(1234,'maria'),
(1235,'tamas'),
(1236,'helia'),
(1234,'maria'),
(1235,'jack'),
(1235,'david')

select distinct id,name  from @test

Answer 3

this would give them in separate table, but @Deepshika solution is fine also.

DECLARE @ID INT
DECLARE @getID CURSOR
SET @getID = CURSOR FOR
select distinct id
from [work].[dbo].[FORM105]
order by id
OPEN @getID
FETCH NEXT
FROM @getID INTO @ID
WHILE @@FETCH_STATUS = 0 
BEGIN 
select distinct id,name
from [work].[dbo].[FORM105]
where id=@ID
FETCH NEXT
FROM @getID INTO @ID
END
CLOSE @getID
DEALLOCATE @getID