比较两个字典并乘以它们的值

Question

I can't seem to be able to fix this problem in python, and I would be really happy if someone could help me. I basically have two dictionaries.

dict_a = { "poop" : 2, "eggs": 3, "pee": 3, "debt": 4 }
dict_b = { "poop" : 10, "pee": 9}

for word, number in dict_a.items():
     if word in dict_b.keys():
           points = dict_a[word] * dict_b[key]
prints(points)

My problem is that it doesnt seem to work hehe. When I'm comparing my two dictionaries, even if they have the same keys, they do not match. Is there any easier way in seeing if two dictionaries have the same keys, and then multiply the keys' values with each other?

I want the result to be points = 47 Because poop has its values 2*10 and pee has 3*9.

Thank you very much in advance :)

Answer 1

try this.

def mult_dicts(dict1, dict2):
  result_dict = {}
  for word in dict1:
    result_dict[word] = dict1[word]
    if word in dict_b:
      result_dict[word] *= dict2[key]
    else:
      result_dict[word] = dict2[key]
  return result_dict

Or, if you only want it to contain entries when the key is in both dictionaries:

def mult_dicts(dict1, dict2):
  result_dict = {}
  for word in dict1:
    if word in dict_b:
      result_dict[word] = dict1[word] * dict2[key]
  return result_dict

Answer 2

here you go:

>>> for x in set(dict_a.keys() + dict_b.keys()):
...     print(x,dict_b.get(x,1)*dict_b.get(x,1))
... 
('pee', 27)
('poop', 20)
('debt', 4)
('eggs', 3)

if you want a dictionary:

>>> { x:dict_a.get(x,1)*dict_b.get(x,1) for x in set(dict_a.keys() + dict_b.keys())}
{'pee': 27, 'poop': 20, 'debt': 4, 'eggs': 3}

if you want list:

>>> [ [x,dict_a.get(x,1)*dict_b.get(x,1)] for x in set(dict_a.keys() + dict_b.keys())]
[['pee', 27], ['poop', 20], ['debt', 4], ['eggs', 3]]

total points:

>>> sum([ dict_a.get(x,1)*dict_b.get(x,1) for x in set(dict_a.keys()) & set(dict_b.keys())])
47

remove sum to see values:

>>> [ dict_a.get(x,1)*dict_b.get(x,1) for x in set(dict_a.keys()) & set(dict_b.keys())]
[27, 20]

Answer 3

This is assuming, of course, that non present values have a cardinality of 1.

dict_a = { "poop" : 2, "eggs": 3, "pee": 3, "debt": 4 }
dict_b = { "poop" : 10, "pee": 9}
result = {}

for key in set(dict_a).union(dict_b):
    result[key] = dict_a.get(key, 1) * dict_b.get(key, 1)

You may also use a defaultdict to prevent the explicit get(x, 1) but its mainly a matter of preference at this point.

Answer 4

       dict_a = { "poop" : 2, "eggs": 3, "pee": 3, "debt": 4 }
       dict_b = { "poop" : 10, "pee": 9}

x=raw_input("Word: ")
if x in dict_a:
    point=dict_a[x]*dict_b[x]
print point

Result: word: poop

20

Edit then:

    dict_a = { "poop" : 2, "eggs": 3, "pee": 3, "debt": 4 }
    dict_b = { "poop" : 10, "pee": 9}


for x in dict_a:
    for y in dict_b:
        point=dict_a[x]*dict_b[y]
        print point

Result: 27 30 18 20 36 40 27 30