参数类型为：（size_t，const char [2]）

Question

//build a greeting const string greeting = "Hello, " + name + "!"; <-- nsme is a string entered in cmd line

//build 2nd and fourth lines of the output
const string spaces(greeting.size()," "); <-- getting red line here
const string second = "* " + spaces + " *";

//build the first and fifth lines
const string first(second.size(), "*"); <-- getting red line here

I understand what the code is trying to do - ie: set the size - but I'm not sure why this isn't working. Intellisense had 'size' in the options list after I hit the '.' following greeting and second so I expected this to work. Using VS2013 pro.

Answer 1

const string spaces(greeting.size()," ");

std::string does not have a constructor that can take those arguments.

What do you expect it to do? If you want a string with N copies of a single character you need to pass it a single character, not an array of characters ie

const string spaces(greeting.size(), ' ');