在声明之前调用函数

Question

The following code runs in PHP

<?php

$foo = "Chocolate milkshake";

go($foo);

function go($param) {
    echo $param;
}

?>

// Output: chocolate milkshake

See this Demo http://codepad.viper-7.com/ToApZa

This code runs without errors and prints specified output, why? I thought this "function hoisting" only occurred in JavaScript

Answer 1

It doesn't matter where you declare your functions in PHP in most cases, as you've just proved :)

Take a look at this page for more details. The key point:

Functions need not be defined before they are referenced, except when a function is conditionally defined as shown in the two examples below.