Java中的运算符类似于python中的//？

Question

Is there a form of the // operator that is used in python that I can use in java, or some sort of workaround? 10 // 3 = 3

Answer 1

In python 3 // act as a floor division by default.

In python 2.2 and later 2.X version we can import it from the __future__

>>> from __future__ import division
>>> 10/3
3.3333333333333335
>>> 10//3
3

In Java: When dividing floating-point variables or values, the fractional part of the answer is represented in the floating-point variable.

float f = 10.0f / 6.0f; // result is 1.6666
double d = 10.0 / 9.0; // result is 1.1111

But for floor in java:

(int)Math.floor(10/3);

Answer 2

public static int python_like_divisor(int x, int y) {
    final remainder = x % y;
    if(remainder != 0) {
        return (x - remainder) / y;
    }
    return x / y;
}

Some basic math knowledge is good ;)

With float-point (float, double etc.) values this method will not work properly.

Answer 3

One thing to notice is:

in python 3:

6 // -132 = -1

in java:

6 / -132 = 0

Answer 4

Java's integer division will act in the same way as the // operator in Python. This means that something like this:

(int) 9/4 == 2 is True

The cast here is even unnecessary because both 9 and 4 are integers. If one was a float or a double this cast would be necessary as java would no longer execute this statement as integer division. To be more explicit you could do this

(int)Math.floor(9 / 4);

which divides the numbers first and then floors the results to the nearest integer.

Answer 5

您可以使用java.lang.Math#floorDiv(int, int)