从 OpenFileDialog 路径/文件名中提取路径

Question

I'm writing a little utility that starts with selecting a file, and then I need to select a folder. I'd like to default the folder to where the selected file was.

OpenFileDialog.FileName returns the full path & filename - what I want is to obtain just the path portion (sans filename) , so I can use that as the initial selected folder .

    private System.Windows.Forms.OpenFileDialog ofd;
    private System.Windows.Forms.FolderBrowserDialog fbd;
    ...
    if (ofd.ShowDialog() == DialogResult.OK)
    {
        string sourceFile = ofd.FileName;
        string sourceFolder = ???;
    }
    ...
    fbd.SelectedPath = sourceFolder; // set initial fbd.ShowDialog() folder
    if (fbd.ShowDialog() == DialogResult.OK)
    {
       ...
    }

Are there any .NET methods to do this, or do I need to use regex, split, trim, etc??

Answer 1

Use the Path class from System.IO . It contains useful calls for manipulating file paths, including GetDirectoryName which does what you want, returning the directory portion of the file path.

Usage is simple.

string directoryPath = Path.GetDirectoryName(filePath);

Answer 2

how about this:

string fullPath = ofd.FileName;
string fileName = ofd.SafeFileName;
string path = fullPath.Replace(fileName, "");

Answer 3

if (openFileDialog1.ShowDialog(this) == DialogResult.OK)
{
    strfilename = openFileDialog1.InitialDirectory + openFileDialog1.FileName;
}

Answer 4

You can use FolderBrowserDialog instead of FileDialog and get the path from the OK result.

FolderBrowserDialog browser = new FolderBrowserDialog();
string tempPath ="";

if (browser.ShowDialog() == DialogResult.OK)
{
  tempPath  = browser.SelectedPath; // prints path
}

Answer 5

Here's the simple way to do It !

string fullPath =openFileDialog1.FileName;
string directory;
directory = fullPath.Substring(0, fullPath.LastIndexOf('\\'));

Answer 6

这就是文件完整路径所需的全部内容

@openFileDialog1.FileName