[英]Getting String input from the user and searching it in an array
I need to get String input from the user and search it in some array and then i need to order the results like 我需要从用户那里获取String输入并在某个数组中搜索它,然后我需要对结果进行排序
like user's input will be like "The mos" and it will show this as result. 用户输入的内容将类似于“ The mos”,并将其显示为结果。
This one was the method i wrote for it but i couldn't complete it: (That is some homework and i need to use self-written data structures and i need to use a hashmap to create a phonebook. If you need my other classes i can update the question.) 这是我为此编写的方法,但我无法完成它:(这是一些作业,我需要使用自行编写的数据结构,并且需要使用哈希图来创建电话簿。如果需要其他课程我可以更新问题。)
public static void searchByName()
{
System.out.println("Name: ");
String nameSearch = input.next();
for(int i=0; i < contactList.bucket.length; i++)
{
Iterator itr = (LinkedListIterator<HashEntry<Integer,Person>>) contactList.bucket[i].iterator();
while(itr.hasNext()){
HashEntry<Integer,Person> he = (HashEntry<Integer, Person>) itr.next();
int similarity = nameSearch.compareTo(he.getValue().getName());
HashEntry<Integer,String>[] similarArray = null;
for(int x=0; x < contactList.bucket[i].size; x++)
{
similarArray[x] = new HashEntry(similarity, he.getValue().getName());
}//end of for loop
}//end of while loop
}//end of for loop
}//end of searchByName
You have to think about how you are going to tell which elements are "similar" to the user's input. 您必须考虑如何判断哪些元素与用户的输入“相似”。
Coming to my mind : 我想到:
When you know what algorithm you want, implementing it should then be easy, but you first need to ask yourself those questions before writting any code . 当您知道想要哪种算法时,实现起来应该很容易,但是在编写任何代码之前 ,您首先需要问自己那些问题 。
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