C文件解析问题

Question

I have a file to read in that is in a format like

3%6%1

5%3%0

4%9%2

I need it in some format where I can save the separate fields from each line, like I suppose I can make a typedef SOMETHING with SOMETHING.num1 = 3, SOMETHING.num2 = 6, SOMETHING.num3 = 1

Here's what I have so far:

#define BUF 128 
#define LINES 100 

char line[LINES][BUF];

FILE *input = NULL; 
int i = 0;
int total = 0;

input = fopen("input.txt", "r");
while(fgets(line[i], BUF, input)) 
{
  /* get rid of ending \n from fgets */
  line[i][strlen(line[i]) - 1] = '\0';
  i++;
}

total = i;

printf("ORIGINAL READ:\n");

for(i = 0; i < total; ++i)
{
  printf("%s\n", line[i]);
}

printf("\nPARSED:\n");

char  *token;
char parsed[LINES][BUF];

for(i=0; i<total; i++)
{
  token = strtok(line[i], "%");

  while(token != NULL)
  {
    strcpy(parsed[i],token);
    token = strtok(NULL, "%");
  }
}

for(i=0; i<total; i++)
{
  printf("%s\n",parsed[i]);
}

The problem is when I print out the values in my parsed array, it seems to only have the last value of each line, (ie for the sample ^ it would output 1,0,2). I'm new to C programming, how can I go about this?

Answer 1

Right now you are using i to index your parsed numbers, but i is also your line index. You need a separate index to keep track of the numbers you have parsed.

int numberCount = 0;

...
    strcpy(parsed[numberCount++],token);
...

for(i=0; i<numberCount; i++)
    printf("%s\n",parsed[i]);