如何用两个点和步骤之间的元素初始化向量C ++

Question

I'm going to initialize a vector that the elements are scaled uniformly between two numbers with known steps. something like this pseudo code.

typedef vector<double> a(startnumber, step, endnumber);

eg

vector<double> a(1, 1, 10); // a = {1, 2, ...., 10};

Is there any way to do it in c++?

Answer 1

Sure:

template <typename T>
std::vector<T> createRange(T start, T end, T step)
{
    std::vector<T> result;
    for (; start < end; start += step) {
        result.push_back(start);
    }
    return result;
}

Anything else is more complicated without really being better (eg something with iota() or generate() ). This'll only work if step > 0. If you want it to work for negative steps, will have to switch on the sign to check start > end in that case instead.