[英]How to catch Exception thrown in a method invoked by using MethodInfo.Invoke?
I have the following codes: 我有以下代码:
using System;
using System.Reflection;
namespace TestInvoke
{
class Program
{
static void Main( string[] args )
{
Method1();
Console.WriteLine();
Method2();
}
static void Method1()
{
try
{
MyClass m = new MyClass();
m.MyMethod( -3 );
}
catch ( Exception e )
{
Console.WriteLine( e.Message );
}
}
static void Method2()
{
try
{
string className = "TestInvoke.MyClass";
string methodName = "MyMethod";
Assembly assembly = Assembly.GetEntryAssembly();
object myObject = assembly.CreateInstance( className );
MethodInfo methodInfo = myObject.GetType().GetMethod( methodName );
methodInfo.Invoke( myObject, new object[] { -3 } );
}
catch ( Exception e )
{
Console.WriteLine( e.Message );
}
}
}
public class MyClass
{
public void MyMethod( int x )
{
if ( x < 0 )
throw new ApplicationException( "Invalid argument " + x );
// do something
}
}
}
Method1 and Method2 both execute MyClass.MyMethod , but Method1 outputs: 方法1和方法2都执行MyClass.MyMethod,但方法一输出:
Invalid argument -3
while Method2 outputs: 而Method2输出:
Exception has been thrown by the target of an invocation.
Could we modify Method2 so it could catch the exception as in Method1 ? 我们可以修改Method2以便它可以像Method1一样捕获异常吗?
Take a look at the InnerException
. 看一下
InnerException
。 In .NET reflection will wrap the exception - which can be useful for knowing how the exception was called. 在.NET中,反射将包装异常-这对于了解异常的调用方式很有用。 See the inner exception property has the exception you are looking for.
请参阅内部异常属性具有您要查找的异常。
So to have the same exception just call Console.WriteLine(e.InnerException.Message)
instead. 因此,要具有相同的异常,只需调用
Console.WriteLine(e.InnerException.Message)
。
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