为什么即使在PHP中成功建立了与镜像文件的连接后，也无法将其上传到远程FTP服务器？

Question

I want to connect to one remote FTP server and upload image file to that server at some specific location. I'm able to connect to the server but not able to upload the file.

Every time the function ftp_put() is returning false. I debugged the code a lot but I'm not understanding where I'm making the mistake.

Following is my code:

HTML code:

<form method="post" enctype="multipart/form-data" action="xyz.php">
  <input type="file" name="student_image" id="student_image" />                  
</form>

PHP code(xyz.php):

  $t = time();
  $allowed_image_extension = array("jpg","jpeg","gif","png","JPG","JPEG","GIF","PNG");
  if(!empty($_FILES['student_image']['name'])) {
    $ext = pathinfo($_FILES['student_image']['name'], PATHINFO_EXTENSION);     
    $student_image_name = 'student_'.$t.'.'.$ext;
    $_POST['student_name'] = $student_image_name;

    $ftp_server="52.237.5.85"; 
    $ftp_user_name="myservercreds"; 
    $ftp_user_pass="MyServerCreds";

    $file = $_FILES['student_image']['name'];//tobe uploaded 
    $remote_file = "/Students/".$_POST['student_name']; 

    // set up basic connection 
    $conn_id = ftp_connect($ftp_server);  

    // login with username and password 
    $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); 


    // upload a file 
    if (ftp_put($conn_id, $remote_file, $file, FTP_ASCII)) { 
      echo "successfully uploaded $file\n"; 
      exit; 
    } else { 
      echo "There was a problem while uploading $file\n"; 
      exit; 
    } 
    // close the connection 
    ftp_close($conn_id);
  }

During debugging I got True and resource everywhere except at one place in a function ftp_put() .

Answer 1

I believe this is likely due to you passing an absolute path as the $remote_file. A failure on ftp_put should mean you can not write to that location, for whatever reason. I believe changing this so that it does not have the / before the path should fix the issue (note that the file will be relative to the ftp user's home dir, which is typically the directory that you are first displayed when you connect via ftp).

This should look like this:

$file = $_FILES['student_image']['tmp_name']; 
$remote_file = "Students/".$_POST['student_name']; 

EDIT: Edited answer to include tmp_name instead of name, this is a two-parter.

Answer 2

You're using the wrong filename:

$file = $_FILES['student_image']['name'];//tobe uploaded 
                                ^^^^^^^^

That is the filename of the file on the USER's computer. PHP doesn't use that. It puts the upload into a random file name, and stores that name in ['tmp_name'] . You want

$file = $_FILES['student_image']['tmp_name'];

instead. Since you're using the wrong filename, a file which DOESN'T exist on the server, ftp_put is properly returning false since that non-existent file can't be read.

Answer 3

also why don't you try to get the ftp errors:

$trackErrors = ini_get('track_errors');
ini_set('track_errors', 1);
if (!@ftp_put($my_ftp_conn_id, $tmpRemoteFileName, $localFileName, FTP_BINARY)) {
   // error message is now in $php_errormsg
   $msg = $php_errormsg;
   ini_set('track_errors', $trackErrors);
   throw new Exception($msg);
}

@ref: How to get the FTP error when using PHP