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您如何在Django中通过传递参数的网址?

[英]How do you make a url that passes a parameter work in Django?

I'm working on registration logic and I can't seem to make the parameter pass in to work properly. 我正在研究注册逻辑,但似乎无法使参数传入以使其正常工作。 The error I get is a 404 page not found. 我得到的错误是找不到404页面。 Previously, I also got a “The view didn't return an HttpResponse object" error. Any help is appreciated. 以前,我还收到“视图未返回HttpResponse对象”错误。我们将提供任何帮助。

Here is my url from urls.py: 这是我来自urls.py的网址:

url(r'^accounts/confirm/(?P<activation_key>\d+)/$', 'mysite.views.confirm', name='confirm'),

This is my views.py: 这是我的views.py:

def confirm(request, activation_key):
    if request.user.is_authenticated():
        HttpResponseRedirect('/home')

    user = Hash.objects.filter(hash_key = activation_key)
    if user:
        user = Hash.objects.get(hash_key = activation_key) 
        user_obj = User.objects.get(username= user.username)
        user_obj.is_active = True
        user_obj.save()

    HttpResponseRedirect('/home')

I send the url with a string that looks like: 我发送带有以下字符串的网址:

"Click the link to activate your account http://www.example.com/accounts/confirm/%s" % (obj.username, activation_key)"

So the link looks like this: http://www.example.com/accounts/confirm/4beo8d98fef1cd336a0f239jf4dc7fbe7bad8849a127d847f 因此,链接如下所示: http : //www.example.com/accounts/confirm/4beo8d98fef1cd336a0f239jf4dc7fbe7bad8849a127d847f

You have two issues here: 您在这里有两个问题:

  1. Remove the trailing / from your pattern, or make it /? 从样式中删除尾随的/或使其为/? so it will be optional. 因此它将是可选的。
  2. /d+ will only match digits, and your link also contains other characters. /d+仅匹配数字,并且您的链接还包含其他字符。 Try [a-z0-9]+ instead. 尝试使用[a-z0-9]+

Complete pattern: 完整模式:

^accounts/confirm/(?P<activation_key>[a-z0-9]+)$

Remove / from end of your url: 从网址末尾删除/

url(r'^accounts/confirm/(?P<activation_key>\d+)$', 'mysite.views.confirm', name='confirm'),

or add / to end of your link: 或在链接末尾添加/

http://www.example.com/accounts/confirm/4beo8d98fef1cd336a0f239jf4dc7fbe7bad8849a127d847f/

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