如何在python中计算两个单词序列

Question

I am trying to find a way to count two word sequence in a list of words using python. I converted the one word list into a list of two words.I then want to try to count the frequency of all the similar two word lists. I tried the counter function but it gives me an unhashable type: 'list'. An example of my code can be seen below:

s = ['one', 'two','three','four','five','six','one','two']

print s
print
p=[]
i=0
for i in range(0,len(s)/2):
    p.append(s[i*2:i*2+2])

print p
wordcounter = Counter(p)

I am trying to have the output so that the most occuring two words are displayed at the top with the number of occurances next to them. Thank you in advance.

Answer 1

Requirement - "I am trying to have the output so that the most occuring two words are displayed at the top with the number of occurances next to them."

You should try Counter.most_common method and tell us if it works for you.

Answer 2

Counter works only with hashable items. Items of p are lists, so they are not hashable. One way to go around it, is to joint the inner list of strings, eg

wordcounter = collections.Counter(" ".join(v) for v in p)
print(wordcounter)
# gives
# Counter({'one two': 2, 'three four': 1, 'five six': 1})

Answer 3

I thought I could do this is a nice one-liner list comp. Turns out its not so nice:

newlist=[ii for n,ii in enumerate([[x,[lst[i:i+2] for i in range(0,len(lst),2)].count(x)] for x in [lst[i:i+2] for i in range(0,len(lst),2)]]) if ii not in [[x,[lst[i:i+2] for i in range(0,len(lst),2)].count(x)] for x in [lst[i:i+2] for i in range(0,len(lst),2)]][:n]]

please have mercy on my soul