C ++如何将名称硬编码为二进制

Question

I have a project that I am working on and I currently have it working to enter my name > then it converts to hex > encrypts it > decrypts it > then prints it. The problem is I need to hard code my name in binary instead of how it currently works. I have no idea how to convert it.

Here is the code snippet. I apologize if I have entered the code wrong. First time posting.

CfinalprAES ofinalprAES;
ofinalprAES.MakeKey("abcdefghabcdefgh", "\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0", 16, 16);
char szDataIn[80];

printf("Enter your Name: ");
scanf("%79s", szDataIn);

char szDataOut[17] = "\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0";
ofinalprAES.EncryptBlock(szDataIn, szDataOut);
CharStr2HexStr((unsigned char*)szDataIn, szHex, 16);
printf("Hex of input: ");
cout << szHex << endl;
CharStr2HexStr((unsigned char*)szDataOut, szHex, 16);
printf("Encrypted: ");
cout << szHex << endl;
memset(szDataIn, 0, 16);
ofinalprAES.DecryptBlock(szDataOut, szDataIn);
CharStr2HexStr((unsigned char*)szDataIn, szHex, 16);
printf("Decrypted: ");
std::stringstream ss;
ss << szHex << endl;
printf("Hex to String: ");
cout << ss.str();

Answer 1

Simple hard coding:

char szDataIn[80] = "Chris Bertsch";

If you want to make that a little bit more obfuscated, you can use hex representations of the characters in your name:

char szDataIn[80] = "\x43\x68\x72\x69\x73\x20\x42\x65\x72\x74\x73\x63\x68";