调用grid.arrange的名称向量

Question

lets say I have a list called ALL with 40 elements, each of which is a ggplot .

if i want to plot one of these i can do

ALL[[1]] 

or

print(ALL)

if i want to plot them all together i can do

grid.arrange(ALL[[1]] ,ALL[[2]], ALL[[3]], ....  )

or

grid.arrange(ALL[[names(ALL)[1]]] ,ALL[[names(ALL)[2]]], ALL[[names(ALL)[3]]], ....  )

This is really tiring with many list elements. But i cannot figure out how to just call grid.arrange to plot all plots. I don't want to apply over the list because i want multiple plots on the same page.

Calling 40 plots to grid.arrange may seem a lot but they are small plots and even for 1:10 plots on a page this is a lot of typing!!!!

Answer 1

Whenever you've got a list (here your ALL ) whose elements are the arguments you'd like passed in to a function (here grid.arrange ), you can use do.call .

This should do the trick:

## Equivalent to grid.arrange(ALL[[1]], ALL[[2]], ..., ALL[[n]])
do.call(grid.arrange, ALL)