Oracle SQL regexp_substr编程问题

Question

Can anyone help me solve this? I'm a bit of a newbie in programming and I'm looking at using REGEXP_SUBSTR in my query. I have a large file and I need to use only certain parts.

I want to convert this: Stuart, Martin E (Martin.Stuart@canadanotes.ca) to this: Martin.Stuart@canadanotes.ca

I'm using regexp_substr and have got it to display everything apart but I have an annoying bracket on the end of the email address I need to get rid of. Can anyone help please?

SELECT regexp_substr ('Stuart, Martin G (Martin.Stuart@canadanotes.ca)', '[^("]+',1,2)
FROM dual;

REGEXP_SUBSTR('STUART,MARTING(
------------------------------
Martin.Stuart@canadanotes.ca)

Answer 1

select regexp_substr ('Stuart, Martin G (Martin.Stuart@canadanotes.ca)', '[^)("]+',1,2) from dual;

只需在[^]内添加右括号

Answer 2

 select regexp_substr ('Stuart, Martin G (Martin.Stuart@canadanotes.ca)', '[^()]+',1,2) from dual;   

works fine. And why are using the literal " in the expression.