[英]How to make an if else condition within a while loop in php?
I want to make an array that looks like this: 我想制作一个看起来像这样的数组:
qqq = [[a,b],[c,d]];
But with the code that I got it makes an output that looks like this: 但是用我得到的代码,它的输出看起来像这样:
qqq= [[a,b],[c,d],];
what should i do to exclude the extra semicolon? 我应该怎么做才能排除多余的分号?
var qqq = [<?php
$aw = "select * from city;";
$wa = mysql_query($aw);
while($aa = mysql_fetch_array($wa))
{
$cc = $aa['Coordinate_id'];
$bb = $aa['city_name'];
echo "[$cc,$bb],";
}
?> ];
Since you are going for a JSON encoded array, please use the following snippet to achieve exactly the same: 由于您要使用JSON编码的数组,因此请使用以下代码片段实现完全相同的效果:
var qqq = <?php
$aw = "select * from city;";
$wa = mysql_query($get_marker);
$arr = array();
while($aa = mysql_fetch_array($wa)) {
$arr[] = array($aa['Coordinate_id'], $aa['city_name']);
}
echo json_encode($arr);
?>;
Replace this: 替换为:
while($aa = mysql_fetch_array($wa))
{
$cc = $aa['Coordinate_id'];
$bb = $aa['city_name'];
echo "[$cc,$bb],";
}
to this: 对此:
$result = '';
while($aa = mysql_fetch_array($wa))
{
$cc = $aa['Coordinate_id'];
$bb = $aa['city_name'];
result.="[$cc,$bb],";
}
echo trim($result,',');
Instead of echo you should use implode like this 而不是回声,您应该使用像这样的内爆
<?php
$aw = "select * from city;";
$wa = mysql_query($get_marker);
$arr = [];
while($aa = mysql_fetch_array($wa))
{
$cc = $aa['Coordinate_id'];
$bb = $aa['city_name'];
$arr[] = "[$cc,$bb]";
}
?>
var qqq = [<?php echo implode(',',$arr)?>];
I think this improves readability as well and is more easily ported to something more manageable 我认为这也提高了可读性,并且更容易移植到更易于管理的地方
Count the number of rows: 计算行数:
$num = mysql_num_rows($aw);
And check if the condition applies that the last loop is occurring by using a counter: 并使用计数器检查条件是否适用于发生最后一个循环:
$i = 0;
while($aa = mysql_fetch_array($wa))
{
$cc = $aa['Coordinate_id'];
$bb = $aa['city_name'];
if ($i < $num)
{
echo "[$cc,$bb],";
}
else
{
echo "[$cc,$bb]";
}
$i++;
}
Finally, note that mysql_* functions are deprecated and should be avoided. 最后,请注意mysql_ *函数已被弃用,应避免使用。 Use PDO or mysqli instead. 改用PDO或mysqli。
Use an array instead of echo and implode outside while loop 使用数组代替echo并在while循环内爆
var qqq = [<?php
$aw = "select * from city;";
$wa = mysql_query($get_marker);
$ret = array();
while($aa = mysql_fetch_array($wa))
{
$cc = $aa['Coordinate_id'];
$bb = $aa['city_name'];
$ret[] = "[$cc,$bb]";
}
echo implode(',', $ret);
?> ];
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