[英]result is concatenating in ajax success
This is my ajax call code...I call this function on body onload. 这是我的ajax调用代码...我在body onload上调用此函数。
function get_booking_id() {
var baseurl = "<?php echo base_url().'index.php/controller_bookplot2/getbookingid'; ?>";
$.ajax({
url: baseurl,
datatype:"html",
success: function(html) {
alert('booking'+html);
$("#booking_id").val(html);
}
});
}
And this is my controller function.. 这是我的控制器功能。
function getbookingid() {
$sql="select IFNULL(max(booking_id),0) as bookingID from booking";
$query=$this->db->query($sql);
if($query->num_rows() > 0) {
foreach($query->result() as $row) {
echo $x=$row->bookingID;
echo $x+1;
}
}
}
So in alert when in database there is no value, it display 1, but next time it display 12 instead of 2. So I think it concatenating the result. 因此,在警报中,当数据库中没有值时,它显示1,但是下次显示12而不是2。因此,我认为它将结果串联起来。 I want to only 2 as alert not 12. What am I doing wrong???
我只想2个警报而不是12个。我在做什么错?
Please remove echo for $x=$row->bookingID; 请删除$ x = $ row-> bookingID的回显; if you don't need in response.
如果您不需要回应。
Updated controller function code: 更新了控制器功能代码:
function getbookingid(){
$sql="select IFNULL(max(booking_id),0) as bookingID from booking";
$query=$this->db->query($sql);
if($query->num_rows() > 0){
foreach($query->result() as $row){
$x=$row->bookingID;
echo $x+1;
}
}
}
When is no value you are getting the value of echo $x+1;, (1) when you return a value you are getting echo $x=$row->bookingID; 当没有值时,您将得到echo $ x + 1;的值;(1)返回值时,您将得到echo $ x = $ row-> bookingID; (the value is 1) and echo $x+1;
(值为1)并回显$ x + 1; (the value is 2, the $x who has the value of 1 plus 1 is 2), so in the script you get 12.
(值是2,值1加1的$ x是2),因此在脚本中得到12。
You can try removing the one of the echos: 您可以尝试删除回声之一:
function getbookingid() {
$sql="select IFNULL(max(booking_id),0) as bookingID from booking";
$query=$this->db->query($sql);
if($query->num_rows() > 0) {
foreach($query->result() as $row) {
$x = $row->bookingID;
echo $x;
}
}
}
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