preg_match正则表达式匹配全字符串

Question

I have a simple regex, but it's matching more than I want...

Basically, I'm trying to match certain operators (eg. > < != = ) followed by a string.

Regex:

/^(<=|>=|<>|!=|=|<|>)(.*)/

Example subject:

>42

What I'm getting:

array (size=3)
  0 => string '>42' (length=3)
  1 => string '>' (length=1)
  2 => string '42' (length=2)

What I'm trying to get:

array (size=2)
  0 => string '>' (length=1)
  1 => string '42' (length=2)

What I don't understand is that my regex works perfectly on Regex101

Edit: To clarify, how can I get rid of the full string match?

Answer 1

Your answer is correct. Group(0) is the whole match . Group(1) if first group and group(2) is the second group.

Answer 2

You are getting all 3 groups \\0 , \\1 , and '\\2'. see the group matching at the bottom of the page

assuming your matches are in $matches you can run array_shift($matches) to remove the '\\0' match if you wish.