[英]How to send 2 select box dynamically generated values via ajax to get 3rd select box values
I'm trying to get 3rd select box values according to first 2 select box selection (dynamic values); 我试图根据前两个选择框选择(动态值)获得第三个选择框值;
jQuery ajax code is (It only works with airport select box) jQuery ajax代码是(仅适用于机场选择框)
$("#airport").change(function() {
var aid=$(this).val();
var dataString = 'aid='+ aid;
$.ajax
({
type: "POST",
url: "booking/findcompany.php",
data: dataString,
cache: false,
success: function(data) {
$("#company").html(data);
}
});
});
<select name="site" id="site" class="site">
<option value="" selected="selected">Select</option>
<option value="1">Site One</option>
<option value="2">Site Two</option>
<option value="3">Site Three</option>
</select>
<select name="airport" id="airport" class="airport">
<option value="1">Airport One</option>
<option value="2">Airport Two</option>
<option value="3">Airport Three</option>
</select>
<select name="company" id="company" class="company">
//Options here based on above 2 selected values
</select>
PHP code is findcompany.php
PHP代码是
findcompany.php
<?php
if($_POST['aid']) {
$aid=$_POST['aid'];
$site=$_POST['sid']; <<<<<< How Can I pass This ID
$compsql=mysql_query("select * from tbl_company Where air_id='$aid' and site_id='$sid'");
while($rows=mysql_fetch_array($compsql)){
$cid=$rows['comp_id'];
$cdata=$rows['comp_title'];
?>
<option value="<?php echo $cid; ?>"><?php echo $cdata; ?></option>
<?php } } ?>
use $('#site').val()
to get the value of the 1st select box, and then add it to your dataString
. 使用
$('#site').val()
获取第一个选择框的值,然后将其添加到dataString
。 So now your js code would look like - 所以现在您的js代码看起来像-
$("#airport").change(function()
{
var aid=$(this).val();
var sid=$('#site').val();
var dataString = 'aid='+ aid +'&sid='+sid;
...
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