行距不起作用

Question

How can I get each player name with its average score on a separate lines, my code is: 如何获得每个球员的名字及其平均分数，我的代码是：

print(sorted(player_averages.items(), key=lambda x: x[1])

I have tried \\n but doesn't work, are there any other creative ways in which this can be achieved? 我尝试了\\n但没有用，是否还有其他创造性的方法可以实现？

Answer 1

Just use a loop to print your players: 只需使用循环来打印您的播放器：

for name, average in sorted(player_averages.items(), key=lambda x: x[1]):
    print(name, average)

To do it on one line, you'll need to use a generator expression formatting each name-average pair: 为此，您需要使用一个生成器表达式来格式化每个名称平均对：

print(*('{}: {}'.format(name, average)
        for name, average in sorted(player_averages.items(), key=lambda x: x[1]),
      sep='\n')