使用 ls 命令在 Linux 中使用完整路径列出文件

Question

Many will found that this is repeating questions but i have gone through all the questions before asked about this topic but none worked for me.

I want to print full path name of the certain file format using ls command so far i found chunk of code that will print all the files in the directory but not full path.

for i in io.popen("ls /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7"):lines() do
  if string.find(i,"%.*$") then 
     print(i) 
  end
end

this will print out all the file in root diractory and subdiratory.

Output:

  0020111118223425.lvf
  2012
  2012 (2009).mp4
  3 Idiots
  Aashiqui 2
  Agneepath.mkv
  Avatar (2009)
  Captain Phillips (2013)
  Cocktail

I want output like:

  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/0020111118223425.lvf           [File in Root Directory]
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/2012/2012.mkv
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/2012 (2009).mp4                [File in Root Directory]
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/3 Idiots/3 Idiots.mkv
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/Aashiqui 2/Aashiqui 2.mkv
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/Avatar (2009)/Avatar (2009).mkv
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/Captain Phillips (2013).mkv
  /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/Cocktail/Cocktail.mkv

EDIT: I have used this all but its not working with my code in LUA.

when I used with my code it displays wrong directory

for i in io.popen("ls -d $PWD/* /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7"):lines() do
    if string.find(i,"%.*$") then
      print("/mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/"..i)
    end
  end

is not finding files in "/mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7" insted its prints the machines root directory files.

Answer 1

You can use

  ls -lrt -d -1 "$PWD"/{*,.*}   

It will also catch hidden files.

Answer 2

你可以试试这个：

ls -d $PWD/*

Answer 3

For listing everything with full path, only in current directory

find $PWD -maxdepth 1

Same as above but only matches a particular extension, case insensitive (.sh files in this case)

find $PWD -maxdepth 1 -iregex '.+\.sh'

$PWD is for current directory, it can be replaced with any directory

mydir="/etc/sudoers.d/" ; find $mydir -maxdepth 1

maxdepth prevents find from going into subdirectories, for example you can set it to "2" for listing items in children as well. Simply remove it if you need it recursive.

To limit it to only files, can use -type f option.

find $PWD -maxdepth 1 -type f

Answer 4

You could easily use the following to list only files:

ls -d -1 $PWD/*.*

the following to list directories:

ls -d -1 $PWD/**

the following to list everything (files/dirs):

ls -d -1 $PWD/**/*

More helpful options:

-d list directories not their content

-R recursive

-1 list one file per line

-l use long listing format

-a list all including entries starting with . and ..

-A list all but don't list implied . and ..

for more info, just type the following

ls --help 

Answer 5

This prints all files, recursively, from the current directory.

find "$PWD" | awk /.ogg/ # filter .ogg files by regex
find "$PWD" | grep .ogg  # filter .ogg files by term
find "$PWD" | ack .ogg   # filter .ogg files by regex/term using https://github.com/petdance/ack2

Answer 6

Print the full path (also called resolved path) with:

realpath README.md

In interactive mode you can use shell expansion to list all files in the directory with their full paths:

realpath *

If you're programming a bash script, I guess you'll have a variable for the individual file names.

Thanks to VIPIN KUMAR for pointing to the related readlink command.

Answer 7

尝试这个 -

readlink -f file.txt

Answer 8

The ls command will only print the name of the file in the directory. Why not do something like

print("/mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/" + i)

This will print out the directory with the filename.

Answer 9

There is more than one way to do that, the easiest I think would be:

find /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7

also this should work:

(cd /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7; ls | xargs -i echo `pwd`/{})

Answer 10

I have had this issue, and I use the following :

ls -dl $PWD/* | grep $PWD

It has always got me the listingI have wanted, but your mileage may vary.

Answer 11

这对我有用：

ls -rt -d -1 $PWD/{*,.*}

Answer 12

you just want the full path why not use the utility meant for that a combination of readlink and grep should get you what you want

grep -R  '--include=*.'{mkv,mp4} ? | cut -d ' ' -f3  | xargs readlink -e # 
the question mark should be replaced with the right pattern - this is almost right
# this is probably the best solution remove the grep part if you dont need a filter
find <dirname> | grep .mkv | xargs readlink -e |  xargs ls --color=auto # only matroska files in the dir and subdirs with nice color - also you can edit ls flags
find /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7 | grep .mkv 
find /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7 | xargs grep -R  '--include=*.'{mkv,mp4} . | cut -d ' ' -f3 # I am sure you can do more with grep 
readlink -f `ls` # in the directory or 

Answer 13

How about:

 du -a [-b] [--max-depth=N] 

That should give you a file and directory listing, relative to your current location. You will get sizes as well (add the '-b' parameter if you want the sizes in bytes). The max-depth parameter may be necessary to "encourage" du to dive deeply enough into your file structure -- or to keep it from getting carried away.

YMMV!
-101-

Answer 14

If you want recursive listing of absolute pathnames within a subdirectory tree, use du and pipe into cut.