简体   繁体   English

使用准备好的语句登录Servlet

[英]Servlet login with prepared statement

I try to find out, where is Error in my Code below: 我尝试找出以下代码中的错误在哪里:

public void service(HttpServletRequest request, HttpServletResponse response){
        try{
            user1 = request.getParameter("nameLog");
            pass1 = request.getParameter("passLog");
            String userid = null;
            String passdb = null;
            String query = "select user, pass from login where `user` = ? and `pass`=?";

            PreparedStatement pst = conn.prepareStatement(query);
            ResultSet rs = pst.executeQuery();
            pst.setString(1, user1);
            pst.setString(2, pass1);

            while(rs.next()){
                userid = rs.getString("user1");
                passdb = rs.getString("pass1");

                pst.executeQuery();
            }
            if(userid.equals(user1)&& passdb.equals(pass1)){
                response.sendRedirect("/WebContent/login/Main.html");

            }


        }catch(Exception ex){
        ex.printStackTrace();
        }
    }

I try to log in to my application (db Column names are user and pass ) but i get an Error: 我尝试登录到我的应用程序(数据库列名称为userpass ),但出现错误:

java.sql.SQLException: No value specified for parameter 1

in this row 在这一行

ResultSet rs = pst.executeQuery();

How can I get rid of this error and log into my Page? 如何摆脱此错误并登录到我的页面?

Thanks 谢谢

Order matters! 订单很重要! You need to pass the parameters before you call executeQuery , like so: 您需要在调用executeQuery之前传递参数,如下所示:

PreparedStatement pst = conn.prepareStatement(query);            
pst.setString(1, user1);
pst.setString(2, pass1);            
ResultSet rs = pst.executeQuery();

You are executing the query before setting the values. 您正在执行查询,然后再设置值。 It should be: 它应该是:

PreparedStatement pst = conn.prepareStatement(query);
pst.setString(1, user1);
pst.setString(2, pass1);

ResultSet rs = pst.executeQuery();

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM