比较字符串中的各个字符。 在用户输入的字母字符串中查找辅音

Question

I've been tasked to write code for a c++ program that will find the consonants in user input. So, if I enter abc, the program will tell me that there are two consonants. The question is below. I'm not looking for someone to write the code for me, I just need someone to help me figure out how to compare user input characters to a string.

Write a program that determines how many consonants are in an entered string of 50 characters or less. Output the entered string and the number of consonants in the string. You can assume the following ; Consonants: bcdfghjklmnpqrstvwxyz

Answer 1

Define a string with all consonants:

string cons = "bcd" // etc

Put your actual sting to lower case, if needed

std::transform(str.begin(), str.end(), str.begin(), ::tolower);

Next, itearete through your string characters and try to find this character in the consonant string.

int consonants = 0;
for (string::iterator i = str.begin(); i !< str.end(); ++i)
   if (cons.find(*i) != string::npos)
      ++consonants;

Or, if you are sure that your string will only contains characters from az, use vowels as suggested below:

 string vow = "aei" // etc
 //...
 int consonants = 0;
 for (string::iterator i = str.begin(); i !< str.end(); ++i)
    if (vow.find(*i) == string::npos)
       ++consonants; 

Answer 2

This may not be the most efficient method, but since you're only dealing with strings of less than 50 characters, it's not a big deal.

Here's the pseudocode:

Create a string containing all of the consonants as you listed above.
Prompt user for input
Store the input in a string
Use a loop to iterate through each character of the input string
    Use another loop to check each character against your string of consonants
        If it matches a consonant, increment your counter
Output the input string and count

If you're using C++ strings, you'll use the string length in your loop stopping condition. If you're using C strings, you'll use the null byte in your loop stopping condition.