[英]How do I send an array of over the RPC?
I have a bit of a difficulty sending arrays over the RPC using the libtirpc
library. 使用
libtirpc
库通过RPC发送数组时,我有些困难。 Sending primitives during a client-server session is as easy as: 在客户机/服务器会话期间发送原语很容易:
// Client-side boilerplate
struct timeval tout = { 1, 0 };
int in = 42;
clnt_call (cln, 1, (xdrproc_t)xdr_int, (char*)&in,
(xdrproc_t)xdr_void, NULL, tout);
// Server-side boilerplate
int in;
svc_getargs (xprt, (xdrproc_t)xdr_int, (char*)&in);
assert (in == 42);
The xdrproc_t
function signature is bool_t (*xdrproc_t) (XDR *, void *, ...);
xdrproc_t
函数签名为bool_t (*xdrproc_t) (XDR *, void *, ...);
. 。 The
xdr_int(3)
, xdr_long(3)
and other primitive serializers have no variable arguments and so they can be used directly using the clnt_call(3)
and svc_getargs(3)
functions. xdr_int(3)
, xdr_long(3)
和其他原始序列化器没有变量参数,因此可以使用clnt_call(3)
和svc_getargs(3)
函数直接使用它们。 The xdr_array(3)
function used to serialize variable length arrays, however, takes much more arguments: 但是,用于序列化可变长度数组的
xdr_array(3)
函数需要更多的参数:
bool_t xdr_array(XDR *xdrs, char **arrp, unsigned int *sizep,
unsigned int maxsize, unsigned int elsize,
xdrproc_t elproc);
The clnt_call(3)
and svc_getargs(3)
functions can't really pass these arguments to the functions, so creating wrapper functions seemed like the cleanest solution to the problem: clnt_call(3)
和svc_getargs(3)
函数实际上无法将这些参数传递给这些函数,因此创建包装函数似乎是解决该问题的最简单方法:
// Client-side boilerplate
long a = 1, b = 2;
long * arr[] = { &a, &b };
unsigned int amount = sizeof(arr) / sizeof(long*);
bool_t xdr_array_wrapper (XDR * xdr, void * ptr) {
return xdr_array (xdr, ptr, &amount, amount,
sizeof(long), (xdrproc_t)xdr_long);
}
struct timeval tout = { 1, 0 };
long out;
clnt_call (cln, 1, (xdrproc_t)xdr_array_wrapper,
(char*)arr, (xdrproc_t)xdr_long, (char*)&out, tout);
// Server-side boilerplate
long * arr[2];
unsigned int amount = sizeof(arr) / sizeof(long*);
bool_t xdr_array_wrapper (XDR * xdr, void * ptr) {
return xdr_array (xdr, ptr, &amount, amount,
sizeof(long), (xdrproc_t)xdr_long);
}
svc_getargs (xprt, (xdrproc_t)xdr_array_wrapper, (char*)arr);
long a = *arr[0], b = *arr[1];
However, for some unknown reason, only the first element of the array (the variable a
) is transferred and the other one contains garbage. 但是,由于某些未知的原因,仅传输数组的第一个元素(变量
a
),而另一个包含垃圾。 What am I doing wrong? 我究竟做错了什么?
You are using xdr_array
incorrectly for two reasons. 您使用
xdr_array
错误有两个原因。
int*
as if it were an array of int
. int*
数组,就好像它是一个int
数组一样。 The correct way of using it goes like this (stolen from IBM and simplified, refer to the link for a more complete treatment): 正确的使用方式是这样的(从IBM窃取并简化,请参阅链接以获取更完整的处理):
typedef struct xarray
{
int size;
int *p_array;
} xarray ;
bool_t xdr_xarray(XDR *xdrs, xarray *p_xarray )
{
return xdr_array(
xdrs,
(char**)(&(p_xarray->p_array)),
&(p_xarray->size),
MAX_INT,
sizeof(int),
(xdrproc_t)xdr_int))
}
Note these thinsg: 请注意以下thinsg:
p_array
is a pointer to a dynamically allocated array. p_array
是指向动态分配数组的指针。 int
, not of pointers. int
而不是指针的数组。 p_array
to xdr_array
so that on decoding it can allocate an array of the required size and assign it to p_array
. p_array
的地址p_array
给xdr_array
以便在解码时它可以分配所需大小的数组并将其分配给p_array
。 If you want fixed-size arrays you need to use xdr_vector
. 如果需要固定大小的数组,则需要使用
xdr_vector
。
typedef struct xvector
{
int vector[42];
} xarray ;
bool_t xdr_xvector(XDR *xdrs, xarray *p_xvector )
{
return xdr_vector(
xdrs,
(char*)p_xvector->vector,
42,
sizeof(int),
(xdrproc_t)xdr_int))
}
Note you still should not use an array of pointers here. 注意,您仍然不应在此处使用指针数组。
An RPC compiler generates XDR procedures automatically from your data structures, so consider using one. RPC编译器会根据您的数据结构自动生成XDR过程,因此请考虑使用其中一种。
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