如何导出向量 <T> :: push_back返回Python？

Question

This problem would be fairly simple and I would misunderstand something trivial. But since I couldn't find a solution for hours, please let me ask a question here.

What I want to do is exporting the push_back method of the std::vector<T> container class with some fixed type T (say double ) to Python using Boost.Python.

To do that, I wrote the following code:

typedef std::vector<double> vector_double;
class_<vector_double>("vector_double")
    .def("append", &vector_double::push_back);

But this doesn't compile with the following error:

/Users/kenta/experiments/bisite/include/bisite/conservation_score.hpp:25:7: note:
      candidate constructor (the implicit default constructor) not viable:
      requires 0 arguments, but 1 was provided
/Users/kenta/experiments/bisite/src/bisite/pybisite.cpp:90:10: error: no
      matching member function for call to 'def'
        .def("append", &vector_double::push_back);
        ~^~~
/usr/local/include/boost/python/class.hpp:234:11: note: candidate template
      ignored: couldn't infer template argument 'F'
    self& def(char const* name, F f)
          ^
/usr/local/include/boost/python/class.hpp:224:11: note: candidate function
      template not viable: requires single argument 'visitor', but 2 arguments
      were provided
    self& def(def_visitor<Derived> const& visitor)

... and more candidates

The type deduction (?) seems to fail but I can't figure out why. When I defined vector_double as a subclass of std::vector<double> , the code above compiled successfully. But I don't want to do that for some reason.

Can you teach me a solution to this problem?

I'm using clang++ with -std=c++11 option and Boost.Python v1.56.0.

Thank you.

Answer 1

It seems to me, that problem is, that there is two version of push_back in C++11. Try to do it this way

static_cast<void (vector_double::*)(const double&)>(&vector_double::push_back);