[英]ignore root element in JAXB
I'm trying to parse an xml file using JAXB. 我正在尝试使用JAXB解析xml文件。 My problem is that I need to skip the root node, If I delete it from the xml file I get what I need, otherwise - I get an empty object.
我的问题是我需要跳过根节点,如果我从xml文件中删除它我得到了我需要的东西,否则 - 我得到一个空对象。
I'll give a simplified xml and my code (It behaves the same way): 我将给出一个简化的xml和我的代码(它的行为方式相同):
XML: XML:
<?xml version="1.0" encoding="utf-8"?>
<Root>
<!-- <Root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="Office.xsd">
-->
<Office>
<Employees>
<Employee>
<name>George</name>
<rank>3</rank>
</Employee>
<Employee>
<name>Michael</name>
<rank>5</rank>
</Employee>
<Employee>
<name>Jeff</name>
<rank>1</rank>
</Employee>
<Employee>
<name>Todd</name>
<rank>7</rank>
</Employee>
<Employee>
<name>Jessica</name>
<rank>5</rank>
</Employee>
</Employees>
</Office>
</Root>
Office class: 办公室课程:
import javax.xml.bind.annotation.*;
import java.util.Vector;
@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class Office {
@XmlElementWrapper(name = "Employees")
@XmlElement(name = "Employee")
private Vector<Employee> employees;
}
Employee class: 员工类:
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAccessType;
@XmlAccessorType(XmlAccessType.FIELD)
public class Employee {
@XmlElement(name="name")
private String name;
@XmlElement(name="rank")
private int rank;
public void promote() {
rank++;
}
}
Driver: 司机:
import javax.xml.stream.*;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Unmarshaller;
import javax.xml.bind.Marshaller;
import java.io.FileReader;
public class Driver {
public static void main (String[] args) {
parseOffice();
}
public static void parseOffice() {
try {
XMLInputFactory f = XMLInputFactory.newInstance();
XMLStreamReader reader = f.createXMLStreamReader(new FileReader("Office.xml"));
JAXBContext context = JAXBContext.newInstance(Office.class);
Unmarshaller unmarshaller = context.createUnmarshaller();
Office office = unmarshaller.unmarshal(reader, Office.class).getValue();
Marshaller marshaller = context.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.marshal(office, System.out);
}
catch (Exception e) {
e.printStackTrace();
}
}
}
Why don't you create a generic root element? 为什么不创建通用的根元素?
@XmlRootElement(name="Root" ...)
public class Root {
@XmlAnyElement(lax=true)
private Object content;
}
Add it to your context and unmarshal. 将其添加到您的上下文并解组。 You should get a
JAXBElement<Office>
as content
. 您应该获得
JAXBElement<Office>
作为content
。
You can parse the XML with a StAX XMLStreamReader
, then advance it to the element you want to unmarshal, and then unmarshal it. 您可以使用StAX
XMLStreamReader
解析XML,然后将其推进到要解组的元素,然后解组它。
I posted a full example that should help on the related question linked below: 我发布了一个完整的示例,可以帮助解决下面链接的相关问题:
Simply add the root class in hierarcy. 只需在hierarcy中添加根类。 And get Office class from Root class.
从Root类获取Office类。
Root Class:- 根类: -
import javax.xml.bind.annotation.*;
import java.util.Vector;
@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class Root {
@XmlElement(name = "Office")
private Office office;
}
Office class 办公室课
import javax.xml.bind.annotation.*;
import java.util.Vector;
@XmlAccessorType(XmlAccessType.FIELD)
public class Office {
@XmlElementWrapper(name = "Employees")
@XmlElement(name = "Employee")
private Vector<Employee> employees;
}
Change in parse method :- 解析方法改变: -
JAXBContext context = JAXBContext.newInstance(Root.class);
Unmarshaller unmarshaller = context.createUnmarshaller();
Root root = unmarshaller.unmarshal(reader, Root.class).getValue();
Office office = root.getOffice();
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