[英]list @property decorated methods in a python class
Is it possible to obtain a list of all @property
decorated methods in a class? 是否可以获取类中所有@property
装饰方法的列表? If so how? 如果可以,怎么办?
Example: 例:
class MyClass(object):
@property
def foo(self):
pass
@property
def bar(self):
pass
How would I obtain ['foo', 'bar']
from this class? 我如何从此类中获得['foo', 'bar']
?
Anything decorated with property
leaves a dedicated object in your class namespace. 任何用property
修饰的东西都会在类名称空间中留下一个专用对象。 Look at the __dict__
of the class, or use the vars()
function to obtain the same, and any value that is an instance of the property
type is a match: 查看类的__dict__
,或使用vars()
函数获得相同的值,并且作为property
类型实例的任何值都是匹配项:
[name for name, value in vars(MyClass).items() if isinstance(value, property)]
Demo: 演示:
>>> class MyClass(object):
... @property
... def foo(self):
... pass
... @property
... def bar(self):
... pass
...
>>> vars(MyClass)
dict_proxy({'__module__': '__main__', 'bar': <property object at 0x1006620a8>, '__dict__': <attribute '__dict__' of 'MyClass' objects>, 'foo': <property object at 0x100662050>, '__weakref__': <attribute '__weakref__' of 'MyClass' objects>, '__doc__': None})
>>> [name for name, value in vars(MyClass).items() if isinstance(value, property)]
['bar', 'foo']
Note that this will include anything that used property()
directly (which is what a decorator does, really), and that the order of the names is arbitrary (as dictionaries have no set order). 请注意,这将包括直接使用property()
(实际上是装饰器所做的事情),并且名称的顺序是任意的(因为字典没有设置顺序)。
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