拆分文件夹路径字符串

Question

If I have a file path such as:

var/www/parent/folder

How would I go about removing the last folder to return:

var/www/parent

The folders could have any names, I'm quite happy using regex.

Thanks in advance.

Answer 1

使用 split->slice->join 函数：

"var/www/parent/folder".split( '/' ).slice( 0, -1 ).join( '/' );

Answer 2

Use the following regular expression to match the last directory part, and replace it with empty string.

/\/[^\/]+$/

---

'var/www/parent/folder'.replace(/\/[^\/]+$/, '')
// => "var/www/parent"

UPDATE

If the path ends with / , the above expression will not match the path. If you want to remove the last part of the such path, you need to use folloiwng pattern (to match optional last / ):

'var/www/parent/folder/'.replace(/\/[^\/]+\/?$/, '')
// => "var/www/parent"

Answer 3

If it's always the last folder you want to get rid of, the easiest method would be to use substr() and lastIndexOf() :

var parentFolder = folder.substr(0, folder.lastIndexOf('/'));

jsfiddle example

Answer 4

This is no specialized version of split per se, but you can split by the path.sep like so:

import path from 'path';

filePath.split(path.sep);