IPC管道通过文件/ dev / ttyS0和/ dev / ttyS1

Question

I want to perform IPC pipe through serial port dev files. here are the requirements first of all I am trying to use

sudo socat /dev/ttyS0,raw,echo=0,crnl /dev/ttyS1,raw,echo=0,crnl

it is giving an error as follows

2014/12/xx 10:33:19 socat[17848] E tcgetattr(4, 0x7fffe76ecaa0): Input/output error

Once the ttyS0 and ttyS1 are connected, I assume we can perform read/write operation as similar as using a pipe(), I will have two programs peer0.c and peer1.c, peer0.c opens /dev/ttyS0 and peer1.c opens /dev/ttyS1, so that read write operation should be as follows

peer0=>ttyS0--->---ttyS1=>peer1
peer0<=ttyS0---<---ttyS1<=peer1

and since /dev/ttyS(0/1) are system wide, i can run peer0.c program in one terminal and peer1.c in another,

Basically, I have linux based embedded application program which when ported to target hardware it will be controlled by linux based PC via minicom UART interface. target opens its ttyS0 to read uart data sent from PC, in PC, commands will be sent to target via minicom. Now I want to run target application in same PC in one terminal and want to send command from another terminal/minicom. Also the communication should be bidirectional

is it possible to achieve this goal? or is there any other similar way to achieve the same?

thanks in advance

Answer 1

如果只想传输文件，请使用协议通过串行链接进行传输，例如ZMODEM（ http://en.wikipedia.org/wiki/ZMODEM ），如果要完整的IPC，请通过链接建立PPP连接（ http://en.wikipedia.org/wiki/Point-to-Point_Protocol ）

Answer 2

 peer0=>ttyS0--->---ttyS1=>peer1 peer0<=ttyS0---<---ttyS1<=peer1 

You seem to want socat to take the part of the --->--- and ---<--- above. This is not possible, because socat had to open ttyS0 and ttyS1 and compete with peer0 for input from ttyS0 as well as with peer1 for input from ttyS1 . To achieve the goal of communicating with an application on one serial port via another port, just connect the two ports with a null modem cable.