如何同时使用：not和：first-child伪选择器

Question

I want to select the first li without class="test" using :not and :first-child pseudoclasses. In this example I try to set color blue to <li>Third</li> :

 ul li { color:red; } ul li:not(.test):first-child { color:blue; } 

 <ul> <li class="test">First</li> <li class="test">Second</li> <li>Third</li> <li>Fourth</li> </ul> 

Answer 1

Why not do the below, which uses a combination of rules to filter the item you need (you can combine rules #1 and #3).

This has the added advantage of it not mattering what the index is of the first item with the class .test

 ul li { /* <-- select all list items */ color: red; } li:not(.test) { /* <-- select all list which arent test */ color: blue; } ul li:not(.test) ~ li { /* <-- select all list items which follow an item without test */ color: red; } 

 <ul> <li class="test">First</li> <li class="test">Second</li> <li>Third</li> <li>Fourth</li> </ul>