此表达式的preg_replace_callback

Question

I have a preg_replace code in my php file:-

preg_replace('/<([^>]+)>/es', "'<'.sanitize('\\1',5).'>'",strip_tags($var, $allowable_tags))

I want to convert it into preg_replace_callback.

preg_replace_callback('/<([^>]+)>/s', function($m){return '<'.sanitize($m,5).'>';},strip_tags($var, $allowable_tags))

But it is not giving the same results. Can someone help?

Answer 1

But it is not giving the same results.

You use '\\\\1' in the preg_replace replacement string. The equivalent in the preg_replace_callback function($m) body were not $m , but $m[1] .

Answer 2

You can also use clean interface of T-Regx library

pattern('<([^>]+)>', 's')->replace($input)->callback(function (Match $m) {
    return '<' . sanitize($m, 5) . '>';
});