使用数据表jquery的codeigniter中的“未定义表数据”

Question

I have been trying to use datatables jquery plugin with codeigniter and still have no luck. 我一直在尝试将datatables jquery插件与codeigniter一起使用，但仍然没有运气。 I'm new with this api. 我是这个API的新手。 (No ignitedTables please, just dataTables jquery plugin). （请没有ignitedTables，只有dataTables jquery插件）。

The view returns: 该视图返回：

Undefined table data 未定义表数据

Please see MVC below: 请在下面查看MVC：

VIEW (where the script is incorporated) VIEW（包含脚本的位置）

<script type="text/javascript">
    $(document).ready(function() {
var oTable = $('#big_table').dataTable( {
    "bProcessing": true,
    "bServerSide": true,
    "sAjaxSource": "<?php echo site_url('home/calendarListAll/') ?>",
            "bJQueryUI": true,
            "sPaginationType": "full_numbers",
            "iDisplayStart ":20,
            "fnInitComplete": function() {
            //oTable.fnAdjustColumnSizing();
     },
            'fnServerData': function(sSource, aoData, fnCallback)
        {
          $.ajax
          ({
            'dataType': 'json',
            'type'    : 'POST',
            'url'     : sSource,
            'data'    : aoData,
            'success' : fnCallback
          });
        }
        } );
    } );
    </script>

    <html>
    <?php echo $this->table->generate(); ?> //this returns "Undefined table data"
    </html>

CONTROLLER CONTROLLER

function __construct()
{
 parent::__construct();
  $this->load->library('Datatables');
  $this->load->library('table');
  $this->load->database();
  $this->load->helper('url');
  $this->load->helper('form');
  $this->load->helper('html');
}

public function calendarListAll()
{
    $this->load->model('counselor');
    $result = $this->counselor->getCalendar();
    echo $this->datatables->generate($result);
}

MODEL 模型

function getCalendar() // get referred_appointments
{

    $counselor_id = $this->session->userdata('counselor_id');

    $query = $this->db->select ('s.first_name as student_fname, s.last_name as student_lname, s.middle_name as student_mname, e.first_name, e.last_name, e.middle_name, re.*, r.student_id, i.*, e.*')
    ->from ('referral as r, student_course_record as scr, curriculum as c, referred_appointment as re, degree as d, course as cc, counselor as ccc,  issue as i, student as s, employee as e')
    ->where ('r.student_id = scr.student_id')
    ->where ('scr.curr_id = c.curr_id')
    ->where ('c.degree_id = d.degree_id')
    ->where ('d.course_id = cc.course_id')
    ->where ('cc.counselor_id = ccc.counselor_id')
    ->where ('r.issue_id = i.issue_id')
    ->where ('r.student_id = s.student_id')
    ->where ('re.referral_id = r.referral_id')
    ->where ('r.employee_id = e.employee_id')
    ->where ('ccc.counselor_id', $counselor_id)
    ->where ('re.status != "C"');
    $ret = $query->get()->result();
    return $ret;

}

Answer 1

Use may it help you CI Help 使用可能对您有帮助CI帮助

$tmpl = array ('table_open' => '<table id="big_table">');
$this->table->set_template($tmpl);

Answer 2

忘记在generate $ this-> table-> generate（$ records）;中传递数据；

使用数据表jquery的codeigniter中的“未定义表数据”

问题描述

2 个解决方案

解决方案1
0 2014-12-19 12:04:56

解决方案2
0 2017-01-31 15:00:01

使用数据表jquery的codeigniter中的“未定义表数据”

问题描述

2 个解决方案

解决方案1 0 2014-12-19 12:04:56

解决方案2 0 2017-01-31 15:00:01

解决方案1
0 2014-12-19 12:04:56

解决方案2
0 2017-01-31 15:00:01