test.c：51：4：错误：从类型'void *'分配给类型'blk时，类型不兼容

Question

    typedef struct abc{

        int a;
        char b;

    }abc;

    typedef abc bkl[1];
    .
    .
    .

    blk b;

b=shmat(shmid, NULL, 0); //This error that (Void *) to blk 
                              //But anyway blk is pointer,it isnt ? 

blk *b;
b=shmat(shmid, NULL, 0); //This is correct, why? b pointor to pointer

Thanks.

Answer 1

blk b;

is the same as:

abc b[1];

b is not a pointer in the sense that you are using it.

b = shmat(shmid, NULL, 0);

is incorrect because you can't assign a pointer to an array. That is wrong exactly the way the following is wrong.

int arr[3];
arr = malloc(sizeof(int)*10);