[英]Accessing nested attributes in overwritten object using Django
posting this here ; 在这里发表; I believe I'll have some trouble figuring it out and it may just save me some time.
我相信我在解决它时会遇到一些麻烦,这可能会节省一些时间。
In python you can do this : 在python中,您可以执行以下操作:
>>> class Toto():
... def w(self):
... print(self.name)
...
...
...
>>> class Tata(Toto):
... name = 'Hehehehe'
...
...
>>>
>>> e = Tata()
>>> e.w()
Hehehehe
>>>
Tough, using Django i'm stuck up with this error in the exact same context : 艰难,使用Django我在完全相同的上下文中陷入了这个错误:
object has no attribute 'name'
So I tried figuring out if some of my objects didn't had an attribute 'name' but it seems they all have it. 因此,我尝试确定我的某些对象是否没有属性“名称”,但似乎它们都具有属性。
Two questions : 两个问题:
Any limitation from Django side for this kind of thing ? 从Django方面对这种事情有什么限制吗?
How can I check which object throws the error so I can check it properly has the attribute ? 如何检查哪个对象引发了错误,以便可以正确地检查它是否具有属性?
I've been able to figure it out ! 我已经知道了!
So Model overwriting creates a new attribute in the host Class 因此,模型覆盖会在宿主类中创建一个新属性
class Base(models.Model):
def __str__(self):
objs = ['Extended'] # name of the overwriting object
for ob in objs:
try:
return getattr(self, ob).name
except:
pass
return 'Unbinded overwritten object'
class Extended(models.Model):
name = models.CharField(max_length=300)
Base gets a new attribute called extended. Base获得了一个称为扩展的新属性。 So accessing custom attributes inside required passing through the overwriting object name.
因此,访问内部的自定义属性需要通过覆盖对象名称进行传递。
> t = Extended(name='test')
> t.save()
> bases = Base.objects.all()
> b[0].Extended.name
'test'
Happy Christmas everybody 大家圣诞节快乐
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