JavaScript：如何访问另一个对象内部的对象原型？

Question

So I think I'm going crazy here. I'm trying to use prototype in my code, so I will have a Layer object that will have a Figure Object that will have a _newFigure function.

Layer = function(){}
Layer.prototype.figure = function(){}
Layer.prototype.figure.prototype._newFigure = function(){
    //(Creates new Figure)
}

What I'm expecting in pseudo-code:

[LayerObject]{
    figure:{
        _newFigure:function(){
            //(Creates new Figure)
        }    
    }
}

Now that, to me , would be the logical thing to do, but for some reason it doens't work. Do you now how can I achieve that? Keep in mind I'm using prototype for performance reasons.

-- thanks in advance --

UPDATE---------------------------------------------------------------------------------------

As Nick said "Why does Layer need to have a Figure on it's prototype? It seems like Layer and Figure our separate entities, and a Layer can have a Figure instance attached to it. Just a thought : )"

So, I've updated the code (now working)

Layer = function(){
    this.figure = new figureHandler(this);
}

function figureHandler(layer){
    this.layer = layer;
}

figureHandler.prototype._newFigure = function(){
    //(Creates new Figure)
}

-- See ya! Thanks for your help :) --

Answer 1

Would something like the following work for you?

Figure = function() {};
Layer = function() {}; 
Layer.prototype.figure = function() {
  return new Figure();
};

It's a bit confusing to me why you would want an interface like layer.figure._newFigure when layer.figure could create a new figure object for you. Perhaps your use case just isn't clear enough to me.

EDIT: Based on the comment to my original response, I assume you mean something like this:

Figure = function(layer) {
  this.layer = layer;
};
Layer = function() {};
Layer.prototype.figure = function() {
  return new Figure(this);
};

Answer 2

I think you may be looking for something like this:

Figure has a Layer instance and a Layer instance has multiple figures. Layer may have a factory that will create Figures having the current Layer instance:

Layer = function Layer(){
  this.figures = [];
};
Layer.prototype.addFigure = function addFigure(arg){
  arg = arg || {};
  arg.layer = this;
  this.figures.push(new Figure(arg));
  return this;//now you can stack functions
}
Figure = function Figure(arg){
  arg = arg || {};
  //layer is not optional
  this.layer = arg.layer 
    || (function(){
      throw new Error('Cannot create figure without layer');
    }());
  this.shape = arg.shape || 'square';
}
var l = new Layer();
l.addFigure({shape:'round'})//stacking next addFigure on next line
  .addFigure();//defaults to square
console.log(l.figures);

More info on constructor functions and prototype here: https://stackoverflow.com/a/16063711/1641941