从表中查找倒数第二行

Question

I have table with dynamic row and I want to find second last row from table.

HTML Code

<table class="table">   
    <tr><td>1</td></tr>
    <tr><td>2</td></tr>
    <tr><td>3</td></tr>
    <tr><td>4</td></tr>
    <tr><td>5</td></tr>
    <tr><td>6</td></tr>
    <tr><td>7</td></tr>
    <tr><td>8</td></tr>
    <tr><td>9</td></tr>
    <tr><td>10</td></tr>
</table>

jQuery Code

alert($(".table").find("tr:last").find("td").html());  

I tried with tr:last but it give me last row with value 10 .

Expected Output

Second last row value 9 instead of 10

JS Fiddle

Answer 1

使用.prev()返回一个元素。

alert($(".table tr:last").prev().find("td").html());

Answer 2

With nth-last-child:

alert($(".table").find("tr:nth-last-child(2)").find("td").html()); 

You could also make it a single selector:

alert($(".table tr:nth-last-child(2) td").html()); 

Answer 3

var total = $(".table").find("tr").length;
alert($(".table").find("tr:nth-child("+(total-1)+")").find("td").html());

Working fiddle

Answer 4

试试这个

$('.table tr:last').prev('tr').html()

Answer 5

使用.eq（）和-1指定最后一个元素...

alert($(".table").find("tr").eq(-2).find("td").html());

Answer 6

Try this,

alert($(".table").find("tr:last").prev().find("td").html());

updated fiddle

Answer 7

Second Last Row Remove

$('tbody tr:last', $("#ctl00_MainContent_rdgImgDig_ctl00")).prev().remove();