[英]Calling super() to parent class using generics
I have several classes that all extend the same abstract class Encoder
. 我有几个类都扩展了相同的
abstract class Encoder
。 The abstract class requires its children to override an abstract method which accepts a generic-typed parameter ( Subscriber<T>
in this example). 抽象类要求其子级覆盖接受泛型类型参数的抽象方法(在此示例中为
Subscriber<T>
)。 Each subclass overriding this method uses a different type for this parameter. 覆盖此方法的每个子类对此参数使用不同的类型。
abstract class Encoder<T> {
protected String mSomeArg;
public Encoder(String someArg) {
mSomeArg = someArg+" super";
}
public abstract void start(Subscriber<T> subscriber);
}
class ExampleEncoder extends Encoder {
public ExampleEncoder(String arg) {
super(arg); // how to make super class get generic type?
// eg: new Encoder<Message>(arg)
}
@Override
public void start(Subscriber<Message> subscriber) {
Message msg = new Message("hi "+mSomeArg);
subscriber.event(msg);
}
}
Sample use case: 示例用例:
Encoder sample = new ExampleEncoder();
sample.start(new Subscriber<Message>() {
@Override
public void event(Message msg) {
Log(msg.text());
}
});
Encoder otherSample = new OtherEncoder();
sample.start(new Subscriber<OtherThing>() {
@Override
public void event(OtherThing thing) {
Log(thing.toString());
}
});
Question: How can each subclass call its super()
with the generic type it requires for this abstract method? 问题:每个子类如何使用此抽象方法所需的泛型类型调用其
super()
?
Note: Using Subscriber<?>
in this abstract method for this example would defeat my purpose of using generics. 注意:对于此示例,在此抽象方法中使用
Subscriber<?>
会破坏我使用泛型的目的。 Also, instantiating each subclass with the generic type it requires (eg: new ExampleEncoder<Message>()
) seems like a plausible workaround, but also seems unnecessary 此外,使用它所需的泛型类型实例化每个子类(例如:
new ExampleEncoder<Message>()
)似乎是一个看似合理的解决方法,但似乎也没有必要
This 这个
class ExampleEncoder extends Encoder {
is a raw-type . 是原型的 。 I'm fairly sure you wanted something like
我很确定你想要的东西
class ExampleEncoder extends Encoder<Message> {
if you want the concrete class to also be generic then you could use 如果你想要具体类也是通用的那么你可以使用
class ExampleEncoder<T> extends Encoder<T>
but you'd need to modify start
to take a Subscriber<T>
. 但是您需要修改
start
以获取Subscriber<T>
。
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