如何检查输入（整数）是否与数组中存在的另一个值（整数）匹配？

Question

I just learned about array and wanted to build a simple program where I use do-while loops to only accept numbers entered that exist in the array but I'm having some trouble see the problem

Scanner input = new Scanner(System.in);
int[] values; 
values = new int[5];
values[0] = 16;
values[1] = 10;
values[2] = 11;
values[3] = 14;
values[4] = 17;
    int value;
    do {
    System.out.println("Enter a number:");
        value = input.nextInt();    
    }
    while(value != values[]);

the rest was going to be "if" statements that contained some out going text based on the which numbers from the array are entered. The "while" condition comes up in an error in the way I entered it as

EDIT: Since this isn't possible in java could I just write !=16,10,11,14,17 without getting an error? The array won't work in the condition so I'm still stuck in figuring a way to including multiple numbers in the condition

Answer 1

The termination condition of your do loop:

while(value != values[])

is not legal Java. You cannot compare an int value to an array and you cannot reference an array using values[] . I don't know what you're trying to accomplish, but you need to put in a specific subscript in the termination condition or modify it in some other way.

Answer 2

As you see it's not possible to just write while(value != values[]) but you can search a value in an array or check if the value is contained in a List:

--- First way

Using a List of integers:

import java.util.Scanner;
import java.util.List;
import java.util.ArrayList;

public class InArrayWithAsListContains {

    public static void main(String[] args)
    {
        Scanner input = new Scanner(System.in);
        int value=0;
        List<Integer> values = new ArrayList<Integer>();

        values.add(16);
        values.add(10);
        values.add(11);
        values.add(14);
        values.add(17);    

        do {
            System.out.println("Enter a number:");
            value = input.nextInt();    
        } while(!values.contains(value)); 
    }
}

A variation to work with a List starting with int[]:

int[] arr = new int[] {16,10,11,14,17};        

// int[] into List<Integer> conversion
for (int i : arr) values.add(i);

--- Second way

Just using arrays and Arrays.binarySearch(values, key)

import java.util.Scanner;
import java.util.Arrays;

public class Program {

    public static void main(String[] args)
    {
        Scanner input = new Scanner(System.in);
        int value=0;
        int[] values = {16,10,11,14,17};

        Arrays.sort(values);

        do {
            System.out.println("Enter a number:");
            value = input.nextInt();    
        } while(Arrays.binarySearch(values, value) < 0); 
    }
}

Answer 3

一个int与一个int[]