[英]Calculating due date using business hours and holidays
I need to calculate due date / end date for SLAs.我需要计算 SLA 的截止日期/结束日期。 As input values I have the start date and a timespan (in minutes).作为输入值,我有开始日期和时间跨度(以分钟为单位)。 This calculation needs to take into account business hours, weekends, and holidays.此计算需要考虑营业时间、周末和节假日。
I've seen a lot of examples where the input is start date and end date, but have been struggling finding anything similar to the above input values.我看过很多例子,其中输入是开始日期和结束日期,但一直在努力寻找与上述输入值类似的东西。
Is there an elegant solution to this problem?这个问题有优雅的解决方案吗? Is there a way to calculate due date without using a loop?有没有一种方法可以在不使用循环的情况下计算截止日期? I can't think of a way to do the calculation without doing something similar to the following terrible algorithm:如果不做类似于以下可怕算法的事情,我想不出一种方法来进行计算:
You need a table with valid business hours, with the weekends and holidays excluded (or marked as weekend/holiday so you can skip them.) Each row represents one day and the number of working hours for that day.您需要一个包含有效营业时间的表格,其中不包括周末和节假日(或标记为周末/节假日,以便您可以跳过它们。)每一行代表一天和当天的工作小时数。 Then you query the business hours table from your start date to the first (min) date where the sum(hours*60) is greater than your minutes parameter, excluding marked weekend/holiday rows.然后您查询营业时间表,从您的开始日期到第一个(分钟)日期,其中总和(小时 * 60)大于您的分钟参数,不包括标记的周末/假日行。 That gives you your end date.这为您提供了结束日期。
Here's the day table:这是日表:
CREATE TABLE [dbo].[tblDay](
[dt] [datetime] NOT NULL,
[dayOfWk] [int] NULL,
[dayOfWkInMo] [int] NULL,
[isWeekend] [bit] NOT NULL,
[holidayID] [int] NULL,
[workingDayCount] [int] NULL,
CONSTRAINT [PK_tblDay] PRIMARY KEY CLUSTERED
(
[dt] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
here's how I populate the table with days:这是我用天填充表格的方式:
CREATE PROCEDURE [dbo].[usp_tblDay]
AS
BEGIN
SET NOCOUNT ON;
DECLARE
@Dt datetime ,
@wkInMo int,
@firstDwOfMo int,
@holID int,
@workDayCount int,
@weekday int,
@month int,
@day int,
@isWkEnd bit
set @workDayCount = 0
SET @Dt = CONVERT( datetime, '2008-01-01' )
while @dt < '2020-01-01'
begin
delete from tblDay where dt = @dt
set @weekday = datepart( weekday, @Dt )
set @month = datepart(month,@dt)
set @day = datepart(day,@dt)
if @day = 1 -- 1st of mo
begin
set @wkInMo = 1
set @firstDwOfMo = @weekday
end
if ((@weekday = 7) or (@weekday = 1))
set @isWkEnd = 1
else
set @isWkEnd = 0
if @isWkEnd = 0 and (@month = 1 and @day = 1)
set @holID=1 -- new years on workday
else if @weekday= 6 and (@month = 12 and @day = 31)
set @holID=1 -- holiday on sat, change to fri
else if @weekday= 2 and (@month = 1 and @day = 2)
set @holID=1 -- holiday on sun, change to mon
else if @wkInMo = 3 and @weekday= 2 and @month = 1
set @holID = 2 -- mlk
else if @wkInMo = 3 and @weekday= 2 and @month = 2
set @holID = 3 -- President’s
else if @wkInMo = 4 and @weekday= 2 and @month = 5 and datepart(month,@dt+7) = 6
set @holID = 4 -- memorial on 4th mon, no 5th
else if @wkInMo = 5 and @weekday= 2 and @month = 5
set @holID = 4 -- memorial on 5th mon
else if @isWkEnd = 0 and (@month = 7 and @day = 4)
set @holID=5 -- July 4 on workday
else if @weekday= 6 and (@month = 7 and @day = 3)
set @holID=5 -- holiday on sat, change to fri
else if @weekday= 2 and (@month = 7 and @day = 5)
set @holID=5 -- holiday on sun, change to mon
else if @wkInMo = 1 and @weekday= 2 and @month = 9
set @holID = 6 -- Labor
else if @isWkEnd = 0 and (@month = 11 and @day = 11)
set @holID=7 -- Vets day on workday
else if @weekday= 6 and (@month = 11 and @day = 10)
set @holID=7 -- holiday on sat, change to fri
else if @weekday= 2 and (@month = 11 and @day = 12)
set @holID=7 -- holiday on sun, change to mon
else if @wkInMo = 4 and @weekday= 5 and @month = 11
set @holID = 8 -- thx
else if @holID = 8
set @holID = 9 -- dy after thx
else if @isWkEnd = 0 and (@month = 12 and @day = 25)
set @holID=10 -- xmas day on workday
else if @weekday= 6 and (@month = 12 and @day = 24)
set @holID=10 -- holiday on sat, change to fri
else if @weekday= 2 and (@month = 12 and @day = 26)
set @holID=10 -- holiday on sun, change to mon
else
set @holID = null
insert into tblDay select @dt,@weekday,@wkInMo,@isWkEnd,@holID,@workDayCount
if @isWkEnd=0 and @holID is null
set @workDayCount = @workDayCount + 1
set @dt = @dt + 1
if datepart( weekday, @Dt ) = @firstDwOfMo
set @wkInMo = @wkInMo + 1
end
END
I also have a holiday table, but everyone's holidays are different:我也有一个假期表,但是每个人的假期都不一样:
holidayID holiday rule description
1 New Year's Day Jan. 1
2 Martin Luther King Day third Mon. in Jan.
3 Presidents' Day third Mon. in Feb.
4 Memorial Day last Mon. in May
5 Independence Day 4-Jul
6 Labor Day first Mon. in Sept
7 Veterans' Day Nov. 11
8 Thanksgiving fourth Thurs. in Nov.
9 Fri after Thanksgiving Friday after Thanksgiving
10 Christmas Day Dec. 25
HTH HTH
This is the best I could do, still uses a loop but uses date functions instead of incrementing a minutes variable.这是我能做的最好的事情,仍然使用循环但使用日期函数而不是增加分钟变量。 Hope you like it.希望你喜欢。
--set up our source data
declare @business_hours table
(
work_day varchar(10),
open_time varchar(8),
close_time varchar(8)
)
insert into @business_hours values ('Monday', '08:30:00', '17:00:00')
insert into @business_hours values ('Tuesday', '08:30:00', '17:00:00')
insert into @business_hours values ('Wednesday', '08:30:00', '17:00:00')
insert into @business_hours values ('Thursday', '08:30:00', '17:00:00')
insert into @business_hours values ('Friday', '08:30:00', '18:00:00')
insert into @business_hours values ('Saturday', '09:00:00', '14:00:00')
declare @holidays table ( holiday varchar(10) ) insert into @holidays values ('2015-01-01') insert into @holidays values ('2015-01-02')
--Im going to assume the SLA of 2 standard business days (0900-1700) = 8*60*2 = 960 declare @start_date datetime = '2014-12-31 16:12:47' declare @time_span int = 960-- time till due in minutes
declare @true bit = 'true' declare @false bit = 'false'
declare @due_date datetime --our output
--other variables declare @date_string varchar(10) declare @today_closing datetime declare @is_workday bit = @true declare @is_holiday bit = @false
--Given our timespan is in minutes, lets also assume we dont care about seconds in start or due dates set @start_date = DATEADD(ss,datepart(ss,@start_date)*-1,@start_date)
while (@time_span > 0) begin
set @due_date = DATEADD(MINUTE,@time_span,@start_date)
set @date_string = FORMAT(DATEADD(dd, 0, DATEDIFF(dd, 0, @start_date)),'yyyy-MM-dd')
set @today_closing = (select convert(datetime,@date_string + ' ' + close_time) from @business_hours where work_day = DATENAME(weekday,@start_date))
if exists((select work_day from @business_hours where work_day = DATENAME(weekday,@start_date)))
set @is_workday = @true
else
set @is_workday = @false
if exists(select holiday from @holidays where holiday = @date_string)
set @is_holiday = @true
else
set @is_holiday = @false
if @is_workday = @true and @is_holiday = @false
begin
if @due_date > @today_closing
set @time_span = @time_span - datediff(MINUTE, @start_date, @today_closing)
else
set @time_span = @time_span - datediff(minute, @start_date, @due_date)
end
set @date_string = FORMAT(DATEADD(dd, 1, DATEDIFF(dd, 0, @start_date)),'yyyy-MM-dd')
set @start_date = CONVERT(datetime, @date_string + ' ' + isnull((select open_time from @business_hours where work_day = DATENAME(weekday,convert(datetime,@date_string))),''))
end
select @due_date
Sql to Calculate due date excluding holidays and considering business hour as below :- < note : - It's working correctly Business hour (8-5) Maintain holiday table Sql计算不包括假期的截止日期并考虑营业时间如下:- <注意:-工作正常营业时间(8-5)维护假期表
CREATE TABLE [dbo].[holiday](
[id] [int] IDENTITY(1,1) NOT NULL,
[region] [nvarchar](10) NULL,
[Hdate] [date] NULL,
)
> >
declare @start datetime= getdate()
declare @slamins int =960 --- SLA time in mins
declare @Country varchar(2)='NA'
declare @start_hour int = 8 -- business start hour
declare @end_hour int = 17 -- business end hour
declare @true bit = 'true'
declare @false bit = 'false'
declare @is_workday bit = @true
declare @is_holiday bit = @false
declare @due_date datetime
declare @today_closing datetime
declare @temp int = 0
declare @holidays table (HDate DateTime) -- Table variable to hold holidayes
---- Get country holidays from table based on the country code (Feel free to remove this or modify as per your DB schema)
Insert Into @Holidays (HDate) Select date from HOLIDAY Where region=@Country and Hdate>=DateAdd(dd, DateDiff(dd,0,@start), 0)
--check for weekends
set @start = case(datepart(dw,@start)+@@datefirst-1)%7
when 0 then Convert(dateTime,CONVERT(varchar,@start+1,101)+' 08:00:00')
when 6 then Convert(dateTime,CONVERT(varchar,@start+2,101)+' 08:00:00')
else @start end
-- check if start time is before business hour
if datepart(hh, @start) < @start_hour set @start = Convert(dateTime,CONVERT(varchar,@start,101)+' 08:00:00')
-- check if start time is after business hour
if datepart(hh, @start) >= @end_hour set @start = Convert(dateTime,CONVERT(varchar,@start+1,101)+' 08:00:00')
-- loop start
while (@slamins > 0)
begin
-- prepared closing date time based on start date
set @today_closing = Convert(dateTime,CONVERT(varchar,@start,101)+' 17:00:00')
set @due_date = @start
-- calculate number of Minute between start date and closing date
set @temp = DATEDIFF(N, @start , @today_closing);
--check for weekends
if (DATEPART(dw, @start)!=1 AND DATEPART(dw, @start)!=7)
set @is_workday = @true
else
set @is_workday = @false
--check for holidays
if (Select Count(*) From @Holidays Where HDATE=DateAdd(dd, DateDiff(dd,0,@start), 0)) = 0
set @is_holiday =@false
else
set @is_holiday = @true
if @is_workday = @true and @is_holiday = @false
begin
if(@temp < @slamins)
begin
set @slamins = @slamins - @temp
end
else
begin
set @due_date = DATEADD(MINUTE,@slamins,@start)
set @slamins = 0
print @due_date
end
end
set @start = Convert(dateTime,CONVERT(varchar,@start+1,101)+' 08:00:00')
end
select @due_date
Here is an option using a WorkSchedule
table, which will contain the business hours that are available to count towards the SLA.这是一个使用WorkSchedule
表的选项,该表将包含可用于计入 SLA 的营业时间。 To account for weekends and holidays, just do not insert records for these days into the WorkSchedule
table.为了考虑周末和假期,不要将这些天的记录插入到WorkSchedule
表中。
This solution also uses a "Tally" table aka numbers table in the due date calc.此解决方案还在到期日计算中使用“Tally”表,即数字表。 I also included debug output to help you see what is going on, so just comment out or uncomment any debug sections to see less/more info.我还包括调试输出以帮助您查看发生了什么,因此只需注释或取消注释任何调试部分即可查看更少/更多信息。
I used SQL temp tables in this example so that you can run it without messing up your current database schema, but you should replace with physical tables if you use this solution.我在这个例子中使用了 SQL 临时表,这样你就可以在不弄乱当前数据库模式的情况下运行它,但是如果你使用这个解决方案,你应该用物理表替换。
Test Data setups:测试数据设置:
CREATE TABLE #WorkSchedule(WorkStart datetime not null primary key, WorkEnd datetime not null);
GO
CREATE TABLE #Tally (N int not null primary key);
GO
--POPULATE TEST DATA
--populate Tally table
insert into #Tally (N)
select top 10000 N = row_number() over(order by o.object_id)
from sys.objects o cross apply sys.objects o2
;
go
--POPULATE WITH DUMMY TEST DATA
INSERT INTO #WorkSchedule(WorkStart, WorkEnd)
SELECT
workStart = dateadd(hour, 8, t.workDate)
, workEnd = dateadd(hour, 17, t.workDate)
FROM (
SELECT top 10000 workDate = dateadd(day, row_number() over(order by o.object_id), '2000-01-01')
FROM sys.objects o cross apply sys.objects o2
) t
--Exclude weekends from work schedule
WHERE datename(weekday, t.workDate) not in ('Saturday','Sunday')
;
GO
Code to calculate Due Date:计算到期日的代码:
SET NOCOUNT ON;
DECLARE @startDate datetime;
DECLARE @SLA_timespan_mins int;
DECLARE @workStartDayOne datetime;
DECLARE @SLA_Adjusted int;
DECLARE @dueDate datetime;
--SET PARAM VALUES HERE FOR TESTING TO ANY DATE/SLA TIMESPAN YOU WANT:
SET @startDate = '2014-01-04 05:00'; --Saturday
SET @SLA_timespan_mins = 10 * 60 ; --10 hrs.
--get the info day 1, since your start date might be after the work start time.
select top 1 @workStartDayOne = s.WorkStart
--increase the SLA timespan mins to account for difference between work start and start time
, @SLA_Adjusted = case when @startDate > s.WorkStart then datediff(minute, s.WorkStart, @startDate) else 0 end + @SLA_timespan_mins
from #WorkSchedule s
where s.WorkEnd > @startDate
and s.WorkStart <> s.WorkEnd
order by s.WorkStart asc
;
--DEBUG info:
select 'Debug Info' as DebugInfo, @startDate AS StartDate, @workStartDayOne as workStartDayOne, @SLA_timespan_mins as SLA_timespan_mins, @SLA_Adjusted as SLA_Adjusted;
--now sum all the non work hours during that period and determine the additional mins that need added.
;with cteWorkMins as
(
SELECT TOP (@SLA_Adjusted)
s.WorkStart, s.WorkEnd
, WorkMinute = dateadd(minute, t.N, cast(s.WorkStart as datetime))
, t.N as MinuteOfWorkDay
, RowNum = row_number() over(order by s.WorkStart, t.N)
FROM #WorkSchedule s
INNER JOIN #Tally t
ON t.N between 1 and datediff(minute, s.WorkStart, s.WorkEnd)
WHERE s.WorkStart >= @workStartDayOne
ORDER BY s.WorkStart, t.N
)
/**/
SELECT @dueDate = m.WorkMinute
FROM cteWorkMins m
WHERE m.RowNum = @SLA_Adjusted
--*/
/**
--DEBUG: this query will show every minute that is accounted for during the Due Date calculation.
SELECT m.*
FROM cteWorkMins m
--WHERE m.RowNum = @SLA_Adjusted
ORDER BY m.WorkMinute
--*/
;
select @dueDate as DueDate;
GO
Test Cleanup:测试清理:
IF object_id('TEMPDB..#WorkSchedule') IS NOT NULL
DROP TABLE #WorkSchedule;
GO
IF object_id('TEMPDB..#Tally') IS NOT NULL
DROP TABLE #Tally;
GO走
as I understood from your question, what you need is as follow正如我从你的问题中了解到的,你需要的是如下
here is what you can do这是你可以做的
declare @start datetime,
@min int,
@days int
set @start= '28 Dec 2014'
set @min = 2200
-- get the number of days
set @days=datediff(day,@start,dateadd(minute,@min,@start))
-- get the due date
select max(Date)
from
(select row_number() over( order by t.Id)-1 as Id,t.Date
from DateMetadata t
inner join BusinessDays b on Day(t.Date) = b.Day
where t.Date > = @start and not exists(select 1 from Holidays h
where h.Day=Day(t.Date)
and h.Month=Month(t.Date))) as p
where p.Id < @days
Note :that DateMetadata table you will setup it in your database once注意:您将在数据库中设置一次 DateMetadata 表
the setup for the above code :上述代码的设置:
create table Holidays(Id int identity(1,1),
Name nvarchar(50),
Day int,
Month int)
create table BusinessDays(Id int identity(1,1),
Name nvarchar(20),
Day int)
-- i am putting some days that are known,
-- it depends on you to define which holidays you want
insert into Holidays (Name,Day,Month) values('Christmas',25,12)
insert into Holidays(Name,Day,Month) values('New Year',31,12)
insert into Holidays(Name,Day,Month) values('Valentine',14,2)
insert into Holidays(Name,Day,Month) values('Mothers day',21,3)
insert into Holidays(Name,Day,Month) values('April fools day',1,4)
-- i am assuming that the business days are from monday till friday and
-- saturday and sunday are off days
insert into BusinessDays(Name,Day) values ('Monday',1)
insert into BusinessDays(Name,Day) values('Tuesday',2)
insert into BusinessDays(Name,Day) values('Wednesday',3)
insert into BusinessDays(Name,Day) values('Thursday',4)
insert into BusinessDays(Name,Day) values('Friday',5)
this table is needed and you will setup it once需要此表,您将设置一次
-- set up a table that contains all dates from now till 2050 for example
-- and you can change the value of 2050 depending on your needs
-- this table you will setup it once
create table DateMetadata(Id int identity(1,1),
Date datetime)
declare @date datetime
set @date='01 Jan 2014'
while @date < '31 Dec 2050'
begin
insert into DateMetadata(Date) values(@date)
set @date = @date + 1
end
if you need any explanation, i am ready如果你需要任何解释,我准备好了
hope it will help you希望它会帮助你
I created a function to calculate due date from the table, once it's populated as per Beth's and others' approaches (various similar methods for doing this, as you can see -- it only took me about an hour to think about all the UK holidays and populate the table including Easter dates up to 2029 without using these exact guides).我创建了一个函数来计算表格中的截止日期,一旦按照 Beth 和其他人的方法填充它(执行此操作的各种类似方法,如您所见——我只花了大约一个小时来考虑所有英国假期并在不使用这些确切指南的情况下填充表格,包括直到 2029 年的复活节日期)。
Note that my table contains SLA in business hours (8 hours in a normal day, 5 days in a normal week), your business hours may vary but you can amend this easily, just make sure your business hours are set the same for both the SLA table and the function below.请注意,我的表格包含营业时间的 SLA(正常一天 8 小时,正常一周 5 天),您的营业时间可能会有所不同,但您可以轻松修改,只需确保您的营业时间设置为相同SLA 表和下面的函数。
Code below is T-SQL (written in SSMS v17.8.1)下面的代码是 T-SQL(用 SSMS v17.8.1 编写)
CREATE FUNCTION [JIRA].[Fn_JIRA_Due_Date] (
@CreatedDate DATETIME, @SLA_Business_Hours INTEGER
) RETURNS DATETIME
AS
-- SELECT [JIRA].[Fn_JIRA_Due_Date]('2019-12-28 08:00:00', 24)
/*
baldmosher™
2019-03-25
* Function returns the DueDate for a JIRA ticket, based on the CreatedDate and the SLA (based on the Issue Type, or the Epic for Tasks) and business hours per date (set in [JIRA].[Ref_JIRA_Business_Hours])
* Called by IUP to store this at the time the ticket is loaded
* Can only consider SLA in Business Hours:
* <24hrs calendar = <8hrs business
* =24hrs calendar = 8hrs business
* >24hrs calendar = 8hrs business * business days
*/
BEGIN
IF @CreatedDate IS NULL OR @SLA_Business_Hours IS NULL RETURN NULL;
DECLARE @SLA_Hours_Remaining SMALLINT = @SLA_Business_Hours;
--SET DATEFIRST 1;
DECLARE @DueDate DATETIME;
DECLARE @BusHrsStart DECIMAL(18,10) = 8 ; -- start of Business Hours (8am)
DECLARE @BusHrsClose DECIMAL(18,10) = 16 ; -- close of Business Hours (4pm)
--DECLARE @WkndStart DECIMAL(18,10) = 6 ; -- start of weekend (Sat)
DECLARE @Hours_Today SMALLINT ; -- # hours left in day to process ticket
-- PRINT 'Created ' + CAST(CAST(@CreatedDate AS DATE) AS VARCHAR(10)) + ' ' + CAST(CAST(@CreatedDate AS TIME) AS VARCHAR(8))
--!!!! extend to the next whole hour just to simplify reporting -- need to work on fixing this eventually
SET @CreatedDate = DATEADD(MINUTE,60-DATEPART(MINUTE,@CreatedDate),@CreatedDate)
-- PRINT 'Rounded ' + CAST(CAST(@CreatedDate AS DATE) AS VARCHAR(10)) + ' ' + CAST(CAST(@CreatedDate AS TIME) AS VARCHAR(8))
--check if created outside business hours and adjust CreatedDate to start the clock first thing at the next business hours start of day (days are checked next)
IF DATEPART(HOUR,@CreatedDate) < @BusHrsStart
--created before normal hours, adjust @CreatedDate later to @BusHrsStart same day
BEGIN
SET @CreatedDate = DATEADD(HOUR,@BusHrsStart,CAST(CAST(@CreatedDate AS DATE) AS DATETIME))
END
IF DATEPART(HOUR,@CreatedDate) >= @BusHrsClose
--created after normal hours, adjust @CreatedDate to @BusHrsStart next day
BEGIN
SET @CreatedDate = DATEADD(HOUR,@BusHrsStart,CAST(CAST(@CreatedDate+1 AS DATE) AS DATETIME))
--adjust CreatedDate to start the clock the next day with >0 business hours (i.e. extend if it falls on a weekend or holiday)
SET @CreatedDate = CAST(@CreatedDate AS DATE)
StartNextWorkingDay:
IF (SELECT TOP(1) [Business_Hours] FROM [JIRA].[Ref_JIRA_Business_Hours] b WHERE b.[Date] = @CreatedDate ORDER BY [Date]) = 0
BEGIN
SET @CreatedDate = DATEADD(DAY,1,@CreatedDate)
GOTO StartNextWorkingDay
END
--DATEADD(DAY, DATEDIFF(DAY,0,@CreatedDate+7)/7*7,0); -- midnight, Monday next week
SET @CreatedDate = DATEADD(HOUR,@BusHrsStart,@CreatedDate); -- BusHrsStart
END
-- PRINT 'Started ' + CAST(CAST(@CreatedDate AS DATE) AS VARCHAR(10)) + ' ' + CAST(CAST(@CreatedDate AS TIME) AS VARCHAR(8))
--third, check the business hours for each date from CreatedDate onwards to determine the relevant DueDate
SET @DueDate = @CreatedDate
-- PRINT 'SLA Hrs ' + CAST(@SLA_Hours_Remaining AS VARCHAR(2))
SET @Hours_Today = @BusHrsStart + (SELECT TOP(1) [Business_Hours] FROM [JIRA].[Ref_JIRA_Business_Hours] b WHERE b.[Date] = CAST(@DueDate AS DATE) ORDER BY [Date]) - DATEPART(HOUR, @CreatedDate)
-- PRINT 'Hrs Today ' + CAST(@Hours_Today AS VARCHAR(2))
DueNextWorkingDay:
IF @SLA_Hours_Remaining > @Hours_Today
BEGIN
-- PRINT 'Due another day'
SET @SLA_Hours_Remaining = @SLA_Hours_Remaining - @Hours_Today --adjust remaining time after today's hours
SET @Hours_Today = (SELECT TOP(1) [Business_Hours] FROM [JIRA].[Ref_JIRA_Business_Hours] b WHERE b.[Date] = CAST(@DueDate AS DATE) ORDER BY [Date])
-- PRINT 'SLA Hrs ' + CAST(@SLA_Hours_Remaining AS VARCHAR(2))
-- PRINT 'Hrs Today ' + CAST(@Hours_Today AS VARCHAR(2))
SET @DueDate = DATEADD(DAY,1,DATEADD(HOUR,@BusHrsStart,CAST(CAST(@DueDate AS DATE) AS DATETIME))) --adjust DueDate to first thing next day
END
IF @SLA_Hours_Remaining <= @Hours_Today
BEGIN
-- PRINT 'Due today'
SET @DueDate = DATEADD(HOUR,@SLA_Hours_Remaining,@DueDate)
END
ELSE
BEGIN
GOTO DueNextWorkingDay
END
-- PRINT 'DueDate ' + CAST(CAST(@DueDate AS DATE) AS VARCHAR(10)) + ' ' + CAST(CAST(@DueDate AS TIME) AS VARCHAR(8))
RETURN @DueDate
END
GO
Table for SLAs: SLA 表:
CREATE TABLE [JIRA].[Ref_JIRA_SLAs](
[SLA_SK] [SMALLINT] IDENTITY(1,1) NOT NULL,
[Project] [VARCHAR](20) NULL,
[Issue_Type] [VARCHAR](50) NULL,
[Epic_Name] [VARCHAR](50) NULL,
[SLA_Business_Hours] [SMALLINT] NULL,
[Comments] [VARCHAR](8000) NULL
) ON [PRIMARY] WITH (DATA_COMPRESSION = PAGE)
GO
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