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从'char'到'const char *'的无效转换

[英]invalid conversion from ‘char’ to ‘const char*’

Seems to be something wrong with string slicing text[i], what's wrong with that ? 字符串切片text [i]似乎有问题,这有什么问题?

Error show up in eclipse 错误显示在日食

invalid conversion from ‘char’ to ‘const char*’ [-fpermissive]  test.cpp    /Standford.Programming  line 17 C/C++ Problem

Code

string CensorString1(string text, string remove){
    for (int i=0;i<text.length();i++){
        string ch = text[i];
    }
}

This line is the problem: 这行是问题所在:

string ch = text[i];

text[i] is a char not a string . text[i]是一个char而不是一个string You are indexing into text remember so if text equals "sometext" and i equals 3 - text[i] means e . 您正在索引text请记住,如果text equals "sometext"i equals 3 - text[i]表示e Change the above code to: 将上面的代码更改为:

char ch = text[i];

Use str.push_back(ch) to append. 使用str.push_back(ch)追加。 Read about std::string::push_back 阅读有关std :: string :: push_back的信息

Appends character c to the end of the string, increasing its length by one. 将字符c追加到字符串的末尾,将其长度增加一。

text[i]

returns a char - so you should use: 返回一个字符-所以您应该使用:

char c = text[i];

otherwise the compiler tries to construct a string from a char , it can only "convert" a const char * as string though. 否则,编译器将尝试从char构造一个string ,但是它只能将const char *转换为字符串。 Thats the reason for the error message. 多数民众赞成在错误消息的原因。

From the name of your function, I guess you want to do this ... 从函数的名称来看,我想您想这样做...

#include <string>
using std::string;
string CensorString1 ( string text, string const & remove ) {
   for(;;) {
      size_t pos = text.find(remove);
      if ( pos == string::npos ) break;
      text.erase(pos,remove.size());
   }
   return text;
}

... or that: ... 或者那个:

#include <string>
using std::string;
string CensorString1 ( string text, string const & remove ) {
   size_t pos = text.find(remove);
   if ( pos != string::npos ) text.erase(pos,remove.size());
   return text;
}

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