Oracle，Hibernate，分组依据，LISTAGG

Question

I have table "Values":

int id;
double amount;
Date date;
String cryptoName;

I need receive result with "date" and list of "cryptoName" and receive something like:

             btc       ltc       drk      42coin
27-DEC-14    0.2       5.0       100.0    0.01
28-DEC-14    0.22      5.5       99.5     0.02
29-DEC-14    0.23      6.1       100.6    0.03
30-DEC-14    0.25      6.0       101.2    0.03

I can do this:

select "Values"."date", LISTAGG("amount", ', ')  WITHIN GROUP (ORDER BY "cryptoName") as "result" from "Values" GROUP BY "Values"."date"

But in this case I receive two columns: "date" and "result" with my list, but I need to receive "date" column, and several columns, depend on how much unique "cryptoName" in table How can I do that?

Answer 1

As of 11g R1 onward you can use PIVOT operator. see for example: http://oracle-base.com/articles/11g/pivot-and-unpivot-operators-11gr1.php

Or you can use DECODE function along with SUM, if you know all unique values of column ctyptoName like this:

select date,
sum(decode(cryptoName,'value1',amount,0)) as Value1
,sum(decode(cryptoName,'value2',amount,0)) as Value2
,...
from Values
group by date