Javascript循环获取并显示数组中的每个第二个字符串

Question

I feel like I had this one in the bag.

Basically, I will create a bill for a client, and I want to set how many installments they can make in order to pay off a service; however, I would like each payment to be bi-monthly, not monthly, eg:

January, March, May, ... vs January, February, March ...

I have entered a value (for when the bill is created) of 2014-01-2014, and temporarily set the installment amount to 12 months, in order to test my work.

The hiddenDate element value will be dynamic, along with the var called maxMonths.

As of now, everything looks great, but not for the months that go past "12"... Can't figure out how to reset a loop value to get this working.

Thanks!

http://jsfiddle.net/scott88/oe52vz3h/2/

JavaScript:

hiddenDate = document.getElementById("hiddenDate").value;
curDate = hiddenDate.split("-");
curMonth = parseInt(curDate[1]);
curDay = parseInt(curDate[2]);
curYear = parseInt(curDate[0]);

maxMonths = 12; // this will be a dynamic amount, set 12 for testing purposes.
months = ["janvier", "février", "mars", "avril", "mai", "juin", "juillet", "août",     "septembre", "octobre", "novembre", "décembre"]
str = "";

moneyTotal = document.getElementById("hiddenTotal").value;
installement = parseFloat(moneyTotal / maxMonths).toFixed(2);

for (var i = curMonth; i < curMonth + maxMonths; i++) {

for (var j = 0; j < i; j++) {

    if (i < months.length) {
        increment = i + j - curMonth;
    } else {
        increment = (i + j - curMonth) - months.length;
    }

}

console.log(increment + " " + months[increment]);
month = months[increment];
str += "<li><span>$" + installement + "</span><span>postdat&eacute; &#8594;</span><span>" +     curDay + " " + month + " " + curYear + "</span></li>";
}
document.getElementById("hiddenTerms").innerHTML = str;

Answer 1

Change the line

month = months[increment];

to be

month = months[increment % 12];

Answer 2

Do you just want to add 2 to the current month, and wrap around if necessary?

This looks like a problem that can be simplified with the modulus operator.

 curMonth = (curMonth + 2) % 12;