将两个不同的数组合并为一个，其中一个是动态的，另一个是静态的

Question

I want to merge three different arrays in a single array, from those, $array2 is dynamic and the others are static. How would I get output from all merged arrays but with $array2 's multiple entries and other's single.

I have 2 problems:

1) If I closed while loop after $arrary2 (before other array), I only get $array2 's last entry...not all

2) Mainly this: if I close the while loop after $output['data'] = array($result); , then the second entry will create a new array...but I want it in a single array. Any help would be appreciated.

Here is part of my code:

<?php
if(mysql_num_rows($result) == 1) {       

    $q2="select `image_kit_id` from `user_transaction` where `user_id`='$col'";

    $r2=mysql_query($q2);

    if($r2) {
        $count=0;
        while($ids=mysql_fetch_array($r2)) {
            $image_kit_id=$ids['image_kit_id'];
            //echo $image_kit_id;
            $q3="select * from `images` where `image_kit_id` = '$image_kit_id'";
            $r3=mysql_query($q3);
            $data=array();
            $i=0;

            while($row1 = mysql_fetch_array($r3)) {
                $arr = array(
                             'imageid' => $row1['image_id'],

                             );
                $data[$i] = $arr;
                $i++;
            }
            $array2 = array($data);
            $count++;

            $array1 = array('user_id'=>$col);

            $array3 = array($data1);
            $array4 = array($data2);
            $array5 = array($data3);

            $result = array_merge($array1, $array2 ,$array3, $array4 ,$array5);

            $output['data'] = array($result);
        }
        ?>

Answer 1

There is logic error in your code. I have corrected that according to my understanding, below. Tell me its working or otherwise what you want.

 $count=0; //here is no use of this, may be you need for counting
 $array2=array();

 while($ids=mysql_fetch_array($r2)) {
     $image_kit_id=$ids['image_kit_id'];

     $q3="select * from `images` where `image_kit_id` = '$image_kit_id'";
     $r3=mysql_query($q3);
     $data=array();

     while($row1 = mysql_fetch_array($r3)) {
         $arr = array('imageid' => $row1['image_id']);
         $data[] = $arr;
     }
     $array2[] = $data;
     $count++;
 }
 $array1 = array('user_id'=>$col);
 $array3 = array($data1);
 $array4 = array($data2);
 $array5 = array($data3);
 $result = array_merge($array1, $array2 ,$array3, $array4 ,$array5);
 $output['data'] = array($result);

---

Also there are some logics are not clear, may be you need that type of $output , so just mentioning my points here:

1) You can directly store $result in $ouput['data']=$result; , coz $result is an array. why you are making is multidimensional by putting it in another array array($result) ?

2) same logic in $array2 , you can directly store $row1['image_id'] in $data[] , coz in $array2 you are only storing image ids, so you don't need associative array to tell that its imageid .

3) same thing is for all other arrays.

If your output format is not specific then I would suggest:

 $array2=array();
 while($ids=mysql_fetch_array($r2)) {
     $image_kit_id=$ids['image_kit_id'];

     $q3="select * from `images` where `image_kit_id` = '$image_kit_id'";
     $r3=mysql_query($q3);
     $data=array();

     while($row1 = mysql_fetch_array($r3)) {
         $data[] = $row1['image_id'];
     }
     $array2[] = $data;
 }

 $output['data'] = array('user_id'=>$col, 'imageids'=>$array2, $data1, $data2, $data3);
   // first two element will have specified key(index), And last three's keys will be `0, 1 & 2` OR you can specify as you need OR remove the keys for first two also then keys will be `0, 1, 2, 3 & 4`.
 //OR remove the ['data'] also
 $ouput=array('user_id'=>$col, 'imageids'=>$array2, 'data1'=>$data1, 'data2'=>$data2, 'data3'=>$data3);