将结构传递给函数并在其中循环

Question

Trying to pass a struct to a function and browse through it. Is this the correct way to pass a struct to a function? The for loop in the function view() doesn't seem to work. Any help with that too would be appreciated.

My structs:

typedef struct {
    char name[20];
    employee *list_employees;
    int empl_count;
} agency;
typedef struct {
    char name[30];
    int age;

} employee;

Important pars of the code:

int main()
{
//...
int nmbr_agencies;
agency *list_agencies = malloc(sizeof(agency) * nmbr_agencies);
view(&list_agencies, &nmbr_agencies);
}
void view(agence *ListA[], int *nmbr)
{
    int i=0;
    for (i = 0; i < *nmbr; i++){
        printf("name of agency: %s\n", ListeA[i]->name);
        printf("number of employees\n, ListeA[i]->empl_count);
    }
}

Answer 1

No.

You should just pass a single array if that is what you have, not pretend (in the call) that you have an array of pointers which you don't have.

Make the function:

void view(const agency *list, size_t number);

and call it like so:

view(list_agencies, nmbr_agencies);

Then inside the function, do direct accesses:

printf("name of agency: %s\n", list[i].name);

since you don't have an array of pointers.