[英]How to efficiently convert a NSInteger into a NSDecimalNumber
So I want to do NSInteger -> NSDecimalNumber
for decimal computation purpose. 所以我想做NSInteger -> NSDecimalNumber
用于十进制计算。
However, the way I am currently doing it, is using NSNumber as an intermediate. 但是,我目前的方式是使用NSNumber作为中间件。
NSInteger -> NSNumber -> NSDecimalNumber
NSInteger myInteger = 41234312;
NSDecimalNumber *myDecimal = [[NSNumber numberWithInteger:myInteger] decimalValue];
Is there a more efficient way to perform this conversion? 有没有更有效的方法来执行此转换?
You don't need to convert it to NSNumber
, You can use : 您不需要将其转换为NSNumber
,您可以使用:
NSDecimalNumber *myDecimal = [NSDecimalNumber numberWithInteger:myInteger];
NSDecimal
number is a subclass of NSNumber
so you can directly use this method. NSDecimal
数是NSNumber
的子类,因此您可以直接使用此方法。
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