用于删除小于x kb的文件的Shell脚本

Question

I'm trying to find out how to write a little script to delete text files that are smaller than 50 Kilobytes but I have had no success.

My attempt looks like this:

#!/bin/bash
for i in *.txt
do
   if [ stat -c %s < 5 ]
   then
     rm $i
   fi
done

I would appriciate some guidance, thank you!

Answer 1

You can directly use find with the size option for this:

find /your/path -name "*.txt" -size -50k -delete
                              ^^^^^^^^^^
                              if you wanted bigger than 50k, you'd say +50

You may want to stick to the files in the current directory, without going down in the directory structure. If so, you can say:

find /your/path -maxdepth 1 -name "*.txt" -size -50k -delete

---

From man find :

-size n[cwbkMG]

File uses n units of space. The following suffixes can be used:

'b' for 512-byte blocks (this is the default if no suffix is used)

'c' for bytes

'w' for two-byte words

'k' for Kilobytes (units of 1024 bytes)

'M' for Megabytes (units of 1048576 bytes)

'G' for Gigabytes (units of 1073741824 bytes)

Answer 2

You should use fedorqui's version, but for reference:

#!/bin/bash
for i in ./*.txt   # ./ avoids some edge cases when files start with dashes
do
  # $(..) can be used to get the output of a command
  # use -le, not <, for comparing numbers
  # 5 != 50k
  if [ "$(stat -c %s "$i")" -le 50000 ]
  then
    rm "$i"  # specify the file to delete      
  fi # end the if statement
done

It's usually easier to write a program piece by piece and verifying that each part works, rather than writing the entire program and then trying to debug it.