在gulp任务中使用node.js函数

Question

I'm looking to integrate more-css( https://github.com/army8735/more ) into my gulp workflow. I've tried several different options. I'm not sure what the syntax to include a function of this type would be. Could someone clarify?

gulp.task('more-css', function () {
  var moreCss = require('more-css');

  return gulp.src('./in')
    .pipe(moreCss.compress('paint.css', true))
    .pipe(gulp.dest('./out'));
});

Answer 1

 var moreCss=require('more-css');
 gulp.task('build', function(){
 var cssFile='paint.css';//path to paint.css
 gulp.src(cssFile)
 .pipe(moreCss.compress(gulp.src(cssFile), true))
 .pipe(gulp.dest('./out'));
});

Answer 2

@Pradyumna's answer is not correct; gulp plugins are basically transform streams. It's not enough to use the node API directly, you have to wrap it in some streaming logic. Having had a brief look around on npm, there isn't a gulp plugin that you can use for more-css , so I made one. Install with:

npm install gulp-more-css --save-dev

And a code example:

var gulp = require('gulp');
var moreCSS = require('gulp-more-css');

gulp.task('default', function() {
    return gulp.src('./in')
        .pipe(moreCSS())
        .pipe(gulp.dest('./out'));
});

https://github.com/ben-eb/gulp-more-css