由filter_var中的运算符链接的php常量列表

Question

I created a class named Sanitize.

I use the filter_var function to filter and sanitize data. I built the filter_var() third parameter from an array: $options which is like the following code:

private $options = array('typeOfData' => array('options' => array(), 'flags' => array()));

I can build an array with the right options, but this method won't work. I wanted only one of either option or flag, it wouldn't be a problem. Unfortunately, I'd like to pass several option or flag constants to filter_var.

For the flags, is it possible to build the wanted result like FLAG1 | FLAG2? If not, should I use filter_var, with a switch to use filter_var depending on the required flags?

This is the current code using filter_var: filter_var($value, $this->filters[$typeOFData], $this->currentOptions);

Answer 1

A class that Sanitizes based on type:

class Sanitize{
private $data;
private $filteredData;
private $options;
private $typeof;
private $filters;

function __contruct($data){

$this->typeof = gettype($data);
$this->data = $data;

switch ($this->typeof){
    case "integer":
       $this->options = array( /* array of options for integer type*/ );
       $this->filters = array( /*array of all filters you want to use on integers*/ )
        break;
    case "string":
       //....
}

private function getSanitized(){

$filtersNum = count($this->filters);

for($x=0;$x<$filtersNum;$x++){

if(allowsOptions($this->filters[$x])){ $options = $this->options; }else{$options = null;}

$this->filteredData = filter_var($this->data, $this->filters[$x], $options)
}
}

private function allowsOptions($filter){
/* all your code to check*/
return true or false
}
}

I hope this helps, If not, let me know.