[英]min and max in Rcpp programs
I was converting an R function into Rcpp function. 我正在将R函数转换为Rcpp函数。 It is all fine but I have difficulties in using the standard max and min function.
一切都很好,但我在使用标准的最大和最小功能方面遇到了困难。 The code below:
代码如下:
#include <math.h>
#include <RcppArmadillo.h>
#include <algorithm>
#include <iostream>
// [[Rcpp::depends(RcppArmadillo)]]
using namespace Rcpp;
using namespace arma;
using namespace std;
double f4RandomC(double x, double a, double b) {
double out, temp;
temp=(log( (a*(1-x)) / (a+x) )) /log(b) ;
out= std::min(1,temp );
return out;
}
returns me error "no matchinf function for call min(int, &double). If possible, I would lioke to use the std:: library min function 返回错误“没有matchinf函数用于调用min(int,&double)。如果可能的话,我会lioke使用std :: library min函数
Just change std::min(1,temp)
to std::min(1.0,temp)
: 只需将
std::min(1,temp)
更改为std::min(1.0,temp)
:
#include <cmath>
#include <Rcpp.h>
// [[Rcpp::export]]
double f4RandomC(double x, double a, double b) {
double out, temp;
temp =(log( (a*(1-x)) / (a+x) )) /log(b) ;
out = std::min(1.0,temp );
return out;
}
I'm assuming this has to do with the template definition of std::min
我假设这与
std::min
的模板定义有关
template <class T> const T& min (const T& a, const T& b);
which is defined in terms of only one type ( T
), whereas you were passing it two data types ( int
and double
). 它只根据一种类型(
T
)定义,而您传递了两种数据类型( int
和double
)。
Or since you are only comparing two values, you could do this a little more concisely by replacing std::min
with the ternary operator ( ?:
): 或者因为你只是比较两个值,你可以通过用三元运算符(
?:
:)替换std::min
更简洁地做到这一点:
double f4RandomC(double x, double a, double b) {
double temp;
temp =(log( (a*(1-x)) / (a+x) )) /log(b) ;
return temp < 1 ? temp : 1;
}
I'm guessing the type deduction is a little more flexible for operator<
than std::min
. 我猜测类型推导对于
operator<
比std::min
更灵活一点。
Two other options with std::min
: std::min
另外两个选项:
// [[Rcpp::export]]
double f4RandomC2(double x, double a, double b) {
double out, temp;
int z = 1;
temp =(log( (a*(1-x)) / (a+x) )) /log(b) ;
out = std::min( static_cast<double>(z),temp );
return out;
}
// [[Rcpp::export]]
double f4RandomC3(double x, double a, double b) {
double out, temp;
int z = 1;
temp =(log( (a*(1-x)) / (a+x) )) /log(b) ;
out = std::min<double>( z,temp );
return out;
}
Although in this case it's certainly much easier to just change 1
to 1.0
than to (unnecessarily) define int z
just to cast it to a double anyways later on. 虽然在这种情况下,将
1
更改为1.0
肯定要比(不必要地)定义int z
更容易,只是为了将其转换为双倍。
You can learn a lot by reading through function / class definitions (as with most programming languages) - cplusplus.com and cppreference.com are pretty standard sources - and it will often make compiler errors seem much less cryptic. 通过阅读函数/类定义(与大多数编程语言一样),您可以学到很多东西--cplusplus.com和cppreference.com是非常标准的资源 - 而且它经常会使编译器错误看起来更加神秘。
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